Question

Assume that the number of hours college students spend working per week is normally distributed with a mean of 18 hours and standard deviation of 4 hours

2. Assume that the number of hours that college students spend working per week is normally distributed with a mean of 18 hours and a standard deviation of 4 hours. a. Mark the 7 hash marks on the x-axis with the appropriate labels in hours worked per week. Recall that the center hash mark on a normal curve represents the mean, and the distance between hash marks is one standard deviation b. In the graph above, shade the region above that represents the proportion of students who work at least 24 hours per week. c. Determine the percentage of college students who work at least 18 hours per week. d. Determine the percent of college students who work between 14 and 26 hours per week. e. Determine the percent of college students who work at least 24 hours a week. f. In a random sample of 500 college students, how many work at least 24 hours per week?

Answer 1

SER HELP OHON t Shaded portion represents the portion of studentohe atleast 24 hours per weeko

Given H= 18 6.4. X denotes the hours of work done by The students in hours. @ PC students work atleast 18 hours per week) -P[x218) ThaNCO = P { x=8 18-18] =P[zzo] = .5 thers the hours percentage of college students who work per week = .5X100 = 504 at least 18 Op students worked areast 24 hocus)- PIX> 243 - P[zz 24-13] =P[2= 6/4] = P[2215] -0-5-P705 251-5) = 0.5-4332 = 0.0668 OP ( 1453 24] = P [14-18 5X-48 5 26-18) - P[-152s ] = P(-15750] + P (os = Plosası]+ p[oszsé] : symmet zic = 0.3413 + 2.08185 = 0.8185 ercentage of College Students who won between 14 and 26 is = 81-85.1

e) P(x224) - P[2224-18 ] =P[7215] = 0.0668 Percentage = 6.687 +) p (x224] =P[221-5) - 0.0668 = 500 per week thens no. of atleast 24 hours Students work -500 X 0.0668 = 33.4 ię 33 Students work at least 24 hour