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M Inbok X The Mylab & Mastering.. $/323770/take ension of some... cuestion 10 3 m Using the method of sections, determine the
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o> HG УНС Bi R at H. Ay 12 KN *3m → aking moment of forces GEM = 0 ( BC x 3) - (Ayx 3) = 0 BC = Ayx3 BC = 20.5 (KN) Positivet is disa tan is clination = 3 angle o o o=45° - Equation becomes 20.5-12-HC sis 45=0 HCE 12.021 (KN) Tension. t>Efx=0 BC + HUsing method of section and equilibrium equation to get the result.

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