Solution :-
1) Rp1=(R1R2/(R1+R2)~71.43 Ohms
Rp2=(R3R4/(R3+R4)~127.3 Ohms
Re=198.7 Ohms
2) I=U/Re=0.12 A
I=I1+I2=I3+I4
I1R1=I2R2
I3R3=I4R4
Solve this system of 3 eqs and get:
I2~0.035A
I4~0.086A
I3~0.044A
I4~0.076A
3) P=I2R
Replace the corresponding I in this formula and make the numerical calculation.
4) Sum of Pi (calculated at point 3) should get Ptot=I2Re~2.861 W
raw the combined series-parallel circuit as a simple circuit. Determine & include on Simple Circuit Schematic:...
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