Question

The equilibrium constant for the following reaction is 1.71×10-2 at 847 °C. 2 SO3(g)2 SO2(g) +...

The equilibrium constant for the following reaction is 1.71×10-2 at 847 °C.

  • 2 SO3(g)2 SO2(g) + O2(g) K = 1.71×10-2 at 847 °C

Calculate the equilibrium constant for the following reactions at 847 °C.


(a)   2 SO2(g) + O2(g)2 SO3(g) K =


(b)   SO3(g) SO2(g) + 1/2 O2(g) K =

Show Approach

0 0
Add a comment Improve this question Transcribed image text
Answer #1

2SO3 198 2 Soz + O₂ (9) (3) K = 1.71 10 2 Equilibrium le constont at 847 C mass action law K is given by [s0,3 [02] (503) 171sos be (6) SO₂(g) + 2 O2 (9) 099 k Let equilibrium constant [s0,3 [0] [sorg] con be written It 어 k [ Length [soa] ² [oz 21

Add a comment
Know the answer?
Add Answer to:
The equilibrium constant for the following reaction is 1.71×10-2 at 847 °C. 2 SO3(g)2 SO2(g) +...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT