If we assume that the model is :
where y is intention to purchase ABBY and x is self esteem
Here as we can see the above output :
1)
Hypothesis for testing that if the model is significant or not
Then test statistic corresponding to this test is given by F ratio which is given above in the second table (ANOVA table)
here
F statistic = 60.914 ~ F1, 43
And corresponding P value is also given in the table
P value = .000 <
which implies that here we have enough evidence to reject null hypothesis
i.e., model is significant.
2)
R square measures the variation explained by the dependent variable on independent variable
As we can see that R square is 0.586
which implies that 58.6 % of variation is explaied by self esteem variable.
Another part :
1)
As we can see that the model output table 3
So slope is 0.688
and intercept is 1.348
So the model is
where y is intention to purchase ABBY and x is self esteem
As we can see that in the last table that p value for both intercept and slope is less than 0.05
which implies both of them are statistically significant.
This regression output is appropriate because we have tested and the whole model and coefficients are significant.
Further we can also see that nearly 58.6 % of variation is explained by the model.
2)
We can Mention that self esteem is important variable in finding intention to purchase
since we can also add more variables in the model to increase the R square so the variation explaied in the model can be increased.
Further we can also say that if we increase the self esteem by 1 unit then intention to purchase will increase by 0.688 units.
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[Marketing] Аавьса Norm: 2- AA EE _{Total 40 marks) Question 1 This question has two parts...
A researcher uses two
regression models to seek answers to two research questions. These
models are:
Y1 = Bo1 + B11X1
Y2 = Bo2 + B12X1 + B22X12
Test the null hypotheses for both models. Use the results of
your analyses to recommend an appropriate model. In each of the
above two cases, state your null and alternative hypotheses,
decision criteria, decision and conclusion.
The level of significance is 5%. The data for this study are
presented in the table...
Models 1-7 are below
Part C: Select one model you would use to explain reading ability.,Then use that model to find the 95% confidence interval estimate for the mean reading ability 95% prediction interval for reading ability When age 6, mem span 4.2 and ig 91. Regression [DataSetll C:\Usersn.little5773 Downloads\child data.sav Variables Entered/Removed Variables Entered Variables Removed Method Model Enter age a. Dependent Variable: reading ability b. All requested variables entered. Model Summary Adjusted R Square Std. Error o R...
Please dont answer by hand writing and show steps clearly. Thank
you
Question 5 Interpret the following computer output as stated Model Summary Adjusted Std. Error of R Square R Square the Estimate 8.70363 Model 840a 705 668 a. Predictors: (Constant), X ANOVA Sum of Squares Model df Si Mean Square 1449.974 75.753 19.141 Regression 1449.974 Residual Total 002a 606.026 2056.000 a. Predictors: (Constant), X b. Dependent Variable: Y Coefficientsa Unstandardized Coefficients Standardized Coefficients Beta Model Std. Error 8.507 175...
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Regression Variables Entered/Removeda Model Variables Entered Variables Removed Method 1 Warranty_Yearsb . Enter a. Dependent Variable: Number_of_people_mentioned b. All requested variables entered. Model Summary Model R R Square Adjusted R Square Std. Error of the Estimate 1 .503a .253 .251 .95930 a. Predictors: (Constant), Warranty_Years ANOVAa Model Sum of Squares df Mean Square F Sig. 1 Regression 80.590 1 80.590 87.574 .000b Residual 237.425 258 .920 Total 318.015 259 a. Dependent Variable: Number_of_people_mentioned b. Predictors: (Constant), Warranty_Years Coefficientsa Model Unstandardized...
Model Summary Model R R Square Adjusted R Square Std. Error of the Estimate 1 .884a .782 .775 1134.08895 a. Predictors: (Constant), Tuition2000 Coefficientsa Model Unstandardized Coefficients Standardized Coefficients t Sig. B Std. Error Beta 1 (Constant) 1133.148 701.455 1.615 .116 Tuition2000 1.692 .160 .884 10.551 .000 a. Dependent Variable: Tuition2008 What is the regression equation? What is the percent of variation in BMI explained by the regression line? Predict 2008 Tuition for Oregon given their 2000 tuition rate. Predict...
6. Interpreting statistical software output in regression Aa Aa Suppose you work in the admissions department of a small liberal arts college. You wonder if you can predict students' college grade point averages (GPAs) by their SAT scores. You randomly select 50 recent graduates and collect their SAT scores and college GPAs. You use a statistical software package to run a regression predicting college GPA from SAT score. Use the following output to answer the questions that follovw Descriptive Statistics...
QUESTION 6 Model Summary Model R R Square Adjusted R Square Std. Error of the Estimate 1 .641a .410 .406 4.507 a. Predictors: (Constant), age 3 groups, Total Mastery, Total Optimism Coefficientsa Model Unstandardized Coefficients Standardized Coefficients t Sig. B Std. Error Beta 1 (Constant) 50.016 1.409 35.508 .000 Total Mastery -.786 .067 -.526 -11.719 .000 Total Optimism -.217 .060 -.164 -3.623 .000 age 3 groups -.712 .275 -.098 -2.588 .010 a. Dependent Variable: Total perceived stress What proportion of...
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