1. Ans: A) 0.1
Explanation: Total population 400
48 are colour blind
So, their frequency is (48/400) = 0.1
As, colour blindness is X-linked and they are hemizygous, so, only one allele is present for that.
So, the allele frequency is same as 0.1.
2) Ans: A (Genetic polymorphism)
Explanation: Geneic polymorphism is a case, when multiple alleles are present at a locus, and in that case at least two alleles occur with a higher frequency.
3) Ans: A (Selection for a recessive allele).
4) Ans: C (Stabilising selection)
Explanation: Stabilising selection is an example of natural selection, where the population mean stabilizes the non-extreme trait (intermediate value) value.
5) Ans: B (disruptive selection)
Explanation: This is a type of selection where extreme values for a trait get favoured over the intermediate values.
6) Ans: C (1/2N)
Question 5: Answer and give explanation In a sample of 400 men, 48 have X-linked color...
Part B - How does this research relate to your biology course? The following graph shows the frequency distribution of a heritable trait -- fur color -- in a hypothetical deer mouse population. The x-axis represents variation in fur color from light to dark. The y-axis represents the percentage of individuals in the population with each particular color of fur. 333 There are three ways in which natural selection can alter the frequency distribution of a heritable trait, such as...
15) Tay-Sachs is inherited as a recessive allele. It is not sex-linked. Homozygous recessive individuals die within the first few years of life. However there is some evidence that heterozygous individuals are more resistant to tuberculosis. Which of the following statement about Tay-Sachs is true? a) This situation is an example of directional selection b) This situation is an example of disruptive (or diversifying) selection c) This situation is an example of stabilizing selection d) This situation is an example...
Hemophilia is an x-linked recessive trait. In a population of 2000 people, 4 women have hemophilia, 30 men have hemophilia, and 80 are carriers of the disorder. What is the frequency of the hemophilia allele? (Assume the population is 50% men and 50% women.) a.0.059 b.0.033 c.0.057 d.0.039 e.0.038 In a population of 15,000 individuals, 1350 express a recessive trait. How many heterozygotes are there expected to be? a.2100 b.3150 c.6300 d.1800 e.4200
NAME: 6. Red-green color deficiency is an X-linked recessive trait. A woman with normal color vision has a father who is color-deficient. The woman has a child with a man with normal color vision. Which phenotype is NOT expected as a possibility for that child? a) a color-deficient male b) a color deficient female c) a male with normal color vision d) a female with normal color vision 7. Which of the individuals in the human pedigree shown below allow...
QUESTION 9 5 pe If the characteristic depicted in the pedigree below is rare and subject to complete penetrance, it is likely to be X-linked recessive? 5 6 7 -OOO No, because individuals ll-2 and 11-4 are not affected No, because individuals 111-4 and III-6 are not affected Yes, because individuals III-4 and III-6 are not affected Yes, because only females are affected in generation 11 1. The gene for cystic fibrosis (normal dominant allele CF and abnormal recessive allele...
Red-green color blindness is X-linked recessive. A woman with normal color vision has a father who is colorblind. The woman has a child with a man with normal color vision. What is the probability their child is a boy and is colorblind? A. 1/8 B. 1/4 C. 1/2 D. 3/4 E. 0
#7a, b, c, d Look at the following pedigree for a sex-linked trait to answer the questions below. a) Is the allele for this trait found on the X or the Y chromosome? __________ b) Is this a dominant or a recessive trait? ___________ c) Give the genotype of all the individuals d) If individual A has children with an unaffected male, what are the chances that her children will have the trait? e) Individual B marries an unaffected woman....
please #11,13,14 Matthew and lane are planning a family of several children and want to know achondroplasic dwarfism. 11. The genotypes of Matthew and Jane are best represented as a. Matthew:AA, Jane: Aa Matthew: Aa, Jane: a Matthewa, lanea d. Matthewa, Jane: Aa e Matthew: Aa Jane Aa 12. The probability that Matthew and Jane's first child will have dwarfism is b. 25% c. SON d. 75% e. 100% Wthree children are born to Matthew and Jane, what are the...
D. 25% orme condition. The male is XX and the female is XY. But X-linked genes have the same effects in mugwumps as in humans. A recessive X-linked allele "n" produces red-green color blindness. The dominant allele "N" produces normal color vision. If a female mugwump with normal color vision mates with a male mugwump, phenotypically normal for color vision but whose mother was color blind, what is the probability that a son from that mating will be color blind?...
What is the mode of inheritance for hypercholesterolemia? a. Autosomal dominant b. Autosomal recessive c. X-linked dominant d. X-linked recessive e. More than one of the above are possible ---------------------------------------------------------------- What is the mode of inheritance for Hunter's syndrome? a. Autosomal dominant b. Autosomal recessive c. X-linked dominant d. X-linked recessive e. More than one of the above are possible. ------------------------------------------------------------ What is the genotype for individual II-3 at the hypercholesterolemia locus (dominant allele is denoted by H, recessive allele...