1) two hetrozygoys blond/brown hair parents have 5 children. what is the probabilty that:
a) the first 3 children will be blond
b) three children will have blond hair
c)at least three children will have blond hair
explain please ...
1. The parents are heterozygous, let their genotypes be Bb and Bb.
Children can have the four possible genotypes- BB,Bb,Bb,bb
Let the genotype of blonde hair be bb.Then probability of a child having bb genotype that is blonde hair is 1/4
a).Therefore probability that the first 3 children will be blonde is 1/4x1/4x1/4=1/64
b). Total number of chidren =5
If 3 chidren have blonde hair then 2 chidren will have brown hair.
Therefore probability that three children will have blond hair= 3/5
c). probability that atleast three children will have blond hair=1-2/5
1) two hetrozygoys blond/brown hair parents have 5 children. what is the probabilty that: a) the...
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