According to figure
3 micro farad and 4 micro farad
So,
resultant capacitance of these two = C2
1/C2 = 1/(3*10^-6) + 1/(4*10^-6)
C2 = 1.714285714 micro F
And C2 is parallel with 2 micro farad
So equivalent capacitance = C2 + 2 = 1.714285714 + 2 = 3.714285714 micro farad
Can someone help with this? A 3.00 -muF and a 4.00 - muF capacitor are connected...
(Phys 232 Hwk 8 ③ 13 or 14 Problem 19.39 Constants A 3.00 pF and a 4.00-F capacitor are connected in series, and this combination is connected in parallel with a 2.00-1F capacitor (Figure 1). Part A What is the net capacitance? Express your answer with the appropriate units. Figure 1 of 1 > HÅR O a? C = 3.00 uF C = 4.00 uF Ceq - Value Units Submit Request Answer C3= 2.00 pF Provide Feedback Next > P...
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