i) The instruction is a branch instruction. Hence the addressing mode is PC relative addressing.
ii) The instruction format is I-type. Hence the addresses of S1 and S2 are located in the bits [25:16]
iii)
Signal | Status |
RegDst | X |
Branch | 1 |
MemRead | X |
MemtoReg | X |
ALUOp | 01 |
ALUSrc | 0 |
RegWrite | 0 |
Explanation:
iv) The value of the zero flag is 1 as Reg[S1] = Reg[S2]
v) The value of PC is 8H + 16H = 1E H
You can comment below the answer, for any doubts, and I will be happy to help!
Please give a thumbs up if my answer could be of help!
All the best!
Q4: Answer the following questions. [7 Marks] The single cycle implementation of MIPS is as shown...
*For a clearer view of the datapath* Answer choices for all Consider the MIPS single cycle datapath shown below. Select the correct control signals that will be generated by the control unit for the following instruction: andi $t0,$t1,4 Instruction (25-01 Shin Jump address (31-0) - left 2) 28 PC +4 [31-28) XCS result left 2 RegDst Jump Branch MemRead Instruction (31-26] MemtoReg Control ALUOP MemWrite ALUSrc RegWrite Instruction (25-21] PC Read address Read register 1 Read Instruction (20-16] Read data...
Assume that ‘slt $1, $2, $3’ is executed with the implementation in the picture. Identify the value of the 9-bit control signals. Add u X ALU result 4 Add Shift left 2 RegDst Branch MemRead MemtoReg Control ALUOP Instruction [31-26 MemWrite ALUSRC RegWrite Instruction [25-21] Read register 1 Read Read PC address Instruction [20-16] data 1 Read Zero register 2 Instruction ALU ALU 31-0] Instruction memory Read data M Read Address Write result u M Instruction [15-11] register data 2...
(o x Add Addresult ALU Shift left 2 Regst Branch MemRead Instruction (31-26) MemtoReg Controll ALUOP MemWrite ALUSC RogWrite Instruction [25-21] Read register 1 Read Instruction (20-16) Read data 1 register 2 Write Read Instruction (15-11) Write data Registers PC Read address Zoro ALU ALU Instruction (31-0) Instruction memory result Address Read data register data 2 **039 -25 Write Data data memory Instruction (15-01 16 Sign- extend ALU control Instruction 15-01 With regards to the single cycle implementation (as shown...
it is the same question A block diagram of MIPS architecture is given below. What is the value of the control bit for each MUX during the execution of the given instruction? Note, you may use N/Aif MUX output is not usefu Add MUX 4 ALU Add, result Shift left 2 RegDst Branch MemRead Instruction (31-26] Control Memto Reg ALUOP Mem Write ALUSrc RegWrite Instruction [25-21) PC Read address Instruction (20-16] MUXT Read register 1 Read Read data 1 register...
A block diagram of MIPS architecture is given below. What is the value of the control bit for each MUX during the execution of the given instruction? Note, you may use N/A if MUX output is not useful. Add MUX 4 ALU Addresult Shift left 2 RegDst Branch MemRead Instruction (31-26] MemtoReg Control ALUOp MemWrite ALUSrc RegWrite Instruction [25-21] PC Read address Read register 1 Read Read data 1 register 2 Write Read MUX 2 Zero Instruction (2016) MUX(1 Instruction...
urgent A block diagram of MIPS architecture is given below. What is the value of the control bit for each MUX during the execution of the given instruction. Note, you may use N/A if MUX output is not useful. >Add u MUX4 ALU 4 - Addresult Shift left 2) RegDst Branch MemRead Instruction (31-26) Control Memto Reg ALUOp MemWrite ALUSC RegWrite Instruction [25-21] PC Read address Instruction (20-16] Read register 1 Read Read data 1 register 2 Write Read MUX...
6. Consider a datapath similar to the one in figure below, but for a processor that only has one type of instruction: unconditional PC-relative branch. What would the cycle time be for this datapath? PCSrc Add ALU Add result Shift +( left 2 Read register 1 ALUSrc, 4 ALU operation PCRead PC-address Read data 1 Registers Read data 2 MemWrite Zero ALU ALU-I Address MemtoReg Instruction register 2 Instruction | Write Read data-M register Write Lu memory Write Data data...
A block diagram of MIPS architecture is given below. What is the value of the control bit for each MUX during the execution of the given instruction? Note, you may use N/A if MUX output is not useful. > Add 2x MUX 4 ALU 4- Addresult Shift left 2 Instruction (31-26] RegDst Branch MemRead MemtoReg Control ALUOP MemWrite ALUSC RegWrite Instruction (25-21) PC Read address Instruction (20-16] Read register 1 Read Read data 1 register 2 Write Read MUX 2...
Question 5 0.25 pts What is the value of the MemWrite control signal? Question 6 0.25 pts What is the value of the ALUSrc control signal? Add Add Sum--(1 4 Shift left 1 Branch MemRead Instruction [6-0] ControMemtoReg MemWrite ALUSrc RegWrite Instruction [19-15]Read Read register 1 Read Read data! PCaddress Instruction [24-20] Zero ALU ALU result register 2 Instruction 31-0 Instruction [11-7 Read1 Address data | Write Read register daiaALU | M Instruction memory Write data Registers Write Data data...
Add 9 MUX 4 4 Addresult ALU Shift left 2 RegDst Branch MemRead Instruction (31-26) Control Memto Reg ALUOD MemWrite ALUSC RegWrite Instruction [25-21) Read PC Read address register 1 Read Instruction (20-16] MUX1 MUX Zero ALU ALU MUX3 M Instruction (31-0) Instruction memory Road Address data Read data 1 register 2 Write Read register data 2 Write data Registers result Instruction (15-11] Fox SX) Data Write data memory 16 32 Instruction (150) Sign- extend ALU control Instruction (5-0)