Question

Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water. suppose 17g of ethane is mixed with 99.6 g oxygen. calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction.

Answer 1

The chemical reaction is written as follows: 2C,H, (g)+70, (g)-4CO, (g)+6H,0(g) The number of moles of ethane is calculated as follows: 17 g xr mor-0.567 mol 30 g The number of moles of oxygen required to react with 0.567 mol of ethane is calculated as follows: 7 mol O 2 mol CH 0.567 mol C,Hsx 1.98 mol The mass of oxvgen that contains 1.98 mol is calculated as follows: 32 1 mol 1.98 molx-63.36 Hence, 63.36 g of oxygen is required to react with 17 g of ethane. But the amount of oxygen given is 99.6 g. Thus, oxygen gas is in excess and ethane is the limiting reagent. The number of moles of carbon dioxide is calculated from the limiting reagent as follows: 4 mol CO 2 mol CH6 0.567 mol C,H, × 1.13 mol The mass of carbon dioxide that contains 1.13 mol is calculated as follows: 1.13 mol x 44g -49.72 g 1 mol Therefore, the maximum mass of carbon dioxide formed is 49.72