Question

СО Gaseous ethane (CH2CH will react with gaseous oxygen (0,) to produce gaseous carbon dioxide (CO2) and gaseous water H,O). Suppose 12.6 g of ethane is mixed with 33. g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 2 significant digits. g x10

Answer 1

on Ethane reacts with O, giving co₂ and H₂o. The chemical reaction is a C₂H6 (9) + O₂(g) → CO₂(g) + H₂O(g) We have to balance the no, of atoms each element. No, of e-atoms at Lotus =2&at Ritis = d. introducing 2 as coefficient before coq, we get. .:: C2H6 (8) + O₂(g) 200₂(g) + H₂O(9), No. of H-atoms at Litlis = 6 & at RoHS 2 intruducing 3 as coefficient before H₂O, weget, C2H6 (9) + O2(g) + 200,+ 3H2O(g). : In the above reaction all atoms (e, H.) are balanced excepting diatom. No, of oratoms at L.H.S =2 & at Ror.sa 7. introducing 7 as coefficient before Op weget. i Cz46(8) + F 02(g) * 2002(8)+ 3 H2O(g),.. in the above rean, each elements no of atoms are equal at both sides but this reaction is not valid because of the presence of fraction no. (7/2). to remove it, we multiply the bothsides by 2. | 26 H6W +17x270267) + (2x2) 60, (V + (223)+ H2008 ::1203 Hc (90 + 702(9.- 4000 (8+ 6 Hz, 0(3) It is the balanced Chemical reaction.

- According to the chemical reaction equation: 2 mole of C Ho reacts with I mole of Oq Producing smole of H₂o. 2. (2x30g)= 60g of C₂H2 reacts with (7X32)g? 224g of Op. producing (6x18g) = 108g of H₂o. Мој09L 44 of 1-н, - 30 атта1 Molar mass of O₂ = .32 g mot Molar miss of H₂O: 218 g mot By the problem, 12.6 g of Cat is mixed with 33 g of Og.. or 12.6g 0.42 mol CH & is combined with 339 .. 30gmoi! 3 1.031 mor og. according to equation; 2 mol Clip reacts with 7 mole o I 20:3. 11. 12. B 11 02, 0.42 12 12 . 22 7 . 7 / +0.42 = 1.47 mol O2. 2M 1.47 mole of Or is required for complete reaction ... of 0.42 mole of CH6 but in reaction mixture there is only 1031mole of Og This Or acts as limiting reagent here . 32gmor!

according to equation, I mole Of completely reacts with a mole est giving &mol H2O. i s Og ninh Cho a b « H₂o. 1.031 ». Os 3...2.." x 1.031) malattie (x1.031) = 0.295 mile e te » 20.884 H30. 2 1031 mole of O₂ completely reacts with 0: 235 mole of er giving 0.884 mole of H₂O. to unreacted to =(0.42 = 0.295) mole = 0.125 mole. . Again, 0.884 mote of H2O = 0.884961 x 18 g mot to - 15.9 g of H₂O ~ 16 g of Higo 16g of Hol is produced when 12.69 of et is mixed with 33 g of O2