a = acceleration of the truck
Vi = initial velocity = 0 m/s
Vf = final velocity = 55 mph = 24.6 m/s
t = time = 27 sec
acceleration is given as
a = (Vf - Vi)/t
a = (24.6 - 0)/27
a = 0.91 m/s2
for the log not to move
fs = static frictional force = ma
us mg = ma
us = a/g = 0.91/9.8 = 0.093
since the 0.840 > us
hence there is little chance the log could have slid out the back
Sapting Learning While hauling a log in the back of a flatbed truck are pulled over...
While hauling a log in the back of a flatbed truck, a driver is pulled over by the state police. Although the log cannot roll sideways, the police claim that the log could have slid out the back of the truck when accelerating from rest. The driver claims that the truck could not possibly accelerate at the level needed to achieve such an effect. Regardless, the police write a ticket, and the driver's court date is approaching. The log has...
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