Question

Adjusting probabilities based on new information Individual IV-3 is born as a male affected with condition B but not condition A. His parents are bred again, and an ultrasound shows that the fetus is another male. The relevant portion of the pedigree is shown below. Use this new information to determine the parents' genotypes (indicated by red arrows). Then calculate the probabilities that the second male offspring will have each condition. Drag one pink label to each pink target and one blue label to each blue target. Then use the white labels to answer questions 1 and 2. Labels can be used once, more than once, or not at all.

Adjusting probabilities based on new information

Individual IV-3 is born as a male affected with condition B but not condition A. His parents are bred again, and an ultrasound shows that the fetus is another male. The relevant portion of the pedigree is shown below.

Use this new information to determine the parents

Answer 1

From the given data, the probable genotype of the IV-3, with perceptive of autosomal inheritance, would be "A" since he does not have condition A. So, both his parents must be in A condition. Thus, the slot (a) and (c) should be filled with A The probable genotype of the IV-3, with perceptive of sex-linked inheritance of would be "X*Y," since he has condition B. So, both his mother's genotype must be XBX* and father's genotype must be XBY. Thus, the slot (b) should be filled withXBYand the slot (d) should be filled with Xy. So. the pedigree is as follows ByPreviously assigned genotypes A xBx IV-3 ? IV-4 The probability of IV-4 will have condition A is 1/36 2. The probability of IV-4 will have condition B is as follows The probability of getting IV-4 individual with condition B is 1/4th The IV-4 is a second male child . So, according to the product rule Thus, the answer is 0.5 orl/2