A car goes around a curve on a road that is banked at an angle of...

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Image for A car goes around a curve on a road that is banked at an angle of 33.5 degree. Even though the road is slick,

Answer 1

Answer #1

if theta is the angle of banking,

tan(theta) = v^2/(g*r)

here, v is speed

g is acceleration due to gravity

and r is radius of curve.

so,

r = v^2/(g*tan(theta))

= 23^2/(9.8*tan(33.5))

= 81.6 m

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Answer 2

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