Question

A 13.5 m boom, AB, of a crane lifting a 3,000 kg load is shown below. The center of mass of the boom is at its geometric center, and the mass of the boom is 2,800 kg.
For the position shown, calculate the following.
tension T in the cable (in N)
N
the force at the axle A (Give the magnitude in newtons and the direction in degrees counterclockwise from the +x-axis. Assume that the +x-axis is to the right.)
magnitude N direction °

A 13.5 m boom, AB, of a crane lifting a 3,000 kg load is shown below. The center of mass of the boom is at its geometric center, and the mass of the boom is 2,800 kg 2007 3000 kg For the position shown, calculate the following tension in the cable (in N) the force at the and A Give the magnitude in newtons and the direction in degree counterclockwise from the Assume that the ai is to the right.) magnitude direction

Answer 1

find net torque at point A due to all the forces and put that equal to 0 .Then find tension.

Answer! Net torque is zero at pant A enet = r, + Tz tez 0 ag=rXT = ACXT = (13.5 Tanio T) anticlockwise z = (mg) X AD = (3000x9, 8) 13.5 cos 30 = 3.43 x 15 Nm (Clockwise) ez= (2800X9.8 X AE = 2800X9.8x Cos 30° (13.5) = 1.60x15 Nm clockwise from o Ezt az= = 5.03X 10 = 2.38 T = T = 2.11N

Part B) :- net force on the axle A is zero at this position .hence no direction.