Homework Answers
Add Answer to:
Force (N) Q4: The results of a tensile test is shown in the 1oooF figure, calculate:...
Please provide me clear handwriting Table 1: TENSILE TEST RESULTS OF A METAL SAMPLE with d...
Please provide me clear handwriting
Table 1: TENSILE TEST RESULTS OF A METAL SAMPLE with d = 7.42, lo = 40mm (4 marks) Load, KN Extension, mm Stress, MPa Strain 0 0 10 0.05 17 0.08 25 0.11 30 0.14 34 0.20 37.5 0.40 38.5 0.60 36 0.90 Cross-sectional Area (A) Modulus of Elasticity (E) Tensile Strength (ST) Percent Elongation (%EL) A = T d2 4 E = Sy Ey ST = PU A %EL = Extension at fracture Gauge...
1. A tensile force of 100 kN is applied on a 0.02 m diameter 2 m...
1. A tensile force of 100 kN is applied on a 0.02 m diameter 2 m length rod. After applying the load, the diameter of the rod decreases to 0.01998 m and the length increases to 2.01 m. What is the Poisson's Ratio of this material? 2. A tensile force of 100 kN is applied on a 0.02 m diameter 2 m length rod. After applying the load, the diameter of the rod decreases to 0.01998 m and the length...
1 Figure 2. The specimen was loaded to 7 You have been provided the tensile test...
1 Figure 2. The specimen was loaded to 7 You have been provided the tensile test results shown in Figure 2. The specimen fracture. Using these results, determine the following: Young's Modulus (3 points). The Yield Stress at 0.2% offset (3 points). The Ultimate Tensile Stress (1 point). The percent elongation at failure (1 point). • The toughness of the material (2 points). --- - -- Stress (o) (MPa) 0.04 0.035 0 0.045 0 0.005 0.01 0.015 0.02 0.025 0.03...
Table 1: TENSILE TEST RESULTS OF A METAL SAMPLE with d= 7.42, lo = 40mm (4...
Table 1: TENSILE TEST RESULTS OF A METAL SAMPLE with d= 7.42, lo = 40mm (4 marks) Load, KN Extension, mm Stress, MPa Strain 0 0 0 0 # 10 0.05 0.0002312 0.00125 17 0.08 0.0003931 0.002 4 25 0.11 0.0005781 0.00275 5 0.14 0.0006937 0.00350 30 34 0.20 0.005 37.5 0.40 0.01 0.0007862 8 0.0008672 2 0.0008903 5 0.0008325 3 38.5 0.60 0.015 36 0.90 0.0225 Cross-sectional Area (A) Modulus of Elasticity (E) Tensile Strength (ST) Percent Elongation (%EL)...
Calculate The modulus of resilience The tensile strength The reduction in area The elongation The engineering...
Calculate
The modulus of resilience
The tensile strength
The reduction in area
The elongation
The engineering stress at fracturg
The modulus of elasticity
The 0.2 offset strength
Problem The following data were collected from a standard 12 mm diameter test specimen of a magnesium alloy (initial :length( Lo = 30.0mm) 20000 15000 10000 5000 0.0 Load (N) 26500 25000 27000 26500 25000 0.15 0.09 0.06 0.03 0.0 AL (mm) 2.10 2.79 1.50 0.90 0.51 After fracture, the total length was...
Given the following data from a tensile test. Show your calculations for the following: Tensile Stress...
Given the following data from a tensile test. Show your
calculations for the following:
Tensile Stress
Modulus of Elasticity (Young’s Modulus)
Yield Strength
Percentage of elongation
Percentage of reduction in area
The following data were collected from a 12-mm-diameter test specimen of magnesium (l. = 30.00 mm): 250 Vielding 0.2% offset Load (N) 0 5,000 10,000 15,000 20,000 25,000 26,500 27,000 26,500 25,000 Gage Length (mm) 0.0000 0.0296 0.0592 0.0888 0.15 0.51 0.90 1.50 (maximum load) 2.10 Stress (MPa) oro...
Assignment 01 TOT Mechanical Properties of Materials 1. A tensile test specimen has a gage length...
Assignment 01 TOT Mechanical Properties of Materials 1. A tensile test specimen has a gage length = 50 mm and its cross-sectional area = 100 mm. The specimen yields at 48,000 N, and the corresponding gage length - 50.23 mm. This is the 0.2 ent yield point. The maximum load of 87,000 N is reached at a gage length 64.2 mm. Determine (a) yield strength, (b) modulus of elasticity, and (c) tensile strength. (d) If fracture occurs at a gage...
1.6 points) A tensile test specimen having a diameter of 10 mm and a gange length...
1.6 points) A tensile test specimen having a diameter of 10 mm and a gange length of 50 mm wa. tested to fracture. The stress-strain curve from the tension test is shown below. Labeling your points and showing the necessary steps, along with the corresponding calculations, find the following magnitudes: (a) Modulus of Elasticity, E = (b) Ultimate Strength = (e) Yield stress (0.2% offset method), (d) If the shear modulus of elasticity of the material is 28 GPa, determine...
question 6 of 25 mm is pulled in tension with a 44,500 N force producing only...
question 6
of 25 mm is pulled in tension with a 44,500 N force producing only elastic detormation . What is oreonding strain and the length between the gage marks when subjected to this force? Given: elastic modulus of copper is 105 GPa. 5. A 10-mm diameter bar of 1040 carbon steel is subjected to a tensile load of 50,000 N, taking it beyond its yield point. Calculate the elastic recov removal of the tensile load. Given: elastic modulus of...
please show step by step solution for problem J (J) For the sleeve and bushing of problem (I) if the pressure at the mating surface is 10,260 psi what is the tensile stress in the sleeve? Tens...
please show step by step solution for problem J
(J) For the sleeve and bushing of problem (I) if the pressure at the mating surface is 10,260 psi what is the tensile stress in the sleeve? Tensile stress = 46,470 psi Answer Box: Enter numerical values in italics t Data Inside radius of inner member Outside radius of inner memeber 0.0000 in b 0.5000 in 0.6250 in δ= 0.0019 in E0 = 3.00E+07 psi E- 300E+07 psi Outside radius of...
Please provide me clear handwriting
Table 1: TENSILE TEST RESULTS OF A METAL SAMPLE with d = 7.42, lo = 40mm (4 marks) Load, KN Extension, mm Stress, MPa Strain 0 0 10 0.05 17 0.08 25 0.11 30 0.14 34 0.20 37.5 0.40 38.5 0.60 36 0.90 Cross-sectional Area (A) Modulus of Elasticity (E) Tensile Strength (ST) Percent Elongation (%EL) A = T d2 4 E = Sy Ey ST = PU A %EL = Extension at fracture Gauge...
1. A tensile force of 100 kN is applied on a 0.02 m diameter 2 m length rod. After applying the load, the diameter of the rod decreases to 0.01998 m and the length increases to 2.01 m. What is the Poisson's Ratio of this material? 2. A tensile force of 100 kN is applied on a 0.02 m diameter 2 m length rod. After applying the load, the diameter of the rod decreases to 0.01998 m and the length...
1 Figure 2. The specimen was loaded to 7 You have been provided the tensile test results shown in Figure 2. The specimen fracture. Using these results, determine the following: Young's Modulus (3 points). The Yield Stress at 0.2% offset (3 points). The Ultimate Tensile Stress (1 point). The percent elongation at failure (1 point). • The toughness of the material (2 points). --- - -- Stress (o) (MPa) 0.04 0.035 0 0.045 0 0.005 0.01 0.015 0.02 0.025 0.03...
Table 1: TENSILE TEST RESULTS OF A METAL SAMPLE with d= 7.42, lo = 40mm (4 marks) Load, KN Extension, mm Stress, MPa Strain 0 0 0 0 # 10 0.05 0.0002312 0.00125 17 0.08 0.0003931 0.002 4 25 0.11 0.0005781 0.00275 5 0.14 0.0006937 0.00350 30 34 0.20 0.005 37.5 0.40 0.01 0.0007862 8 0.0008672 2 0.0008903 5 0.0008325 3 38.5 0.60 0.015 36 0.90 0.0225 Cross-sectional Area (A) Modulus of Elasticity (E) Tensile Strength (ST) Percent Elongation (%EL)...
Calculate
The modulus of resilience
The tensile strength
The reduction in area
The elongation
The engineering stress at fracturg
The modulus of elasticity
The 0.2 offset strength
Problem The following data were collected from a standard 12 mm diameter test specimen of a magnesium alloy (initial :length( Lo = 30.0mm) 20000 15000 10000 5000 0.0 Load (N) 26500 25000 27000 26500 25000 0.15 0.09 0.06 0.03 0.0 AL (mm) 2.10 2.79 1.50 0.90 0.51 After fracture, the total length was...
Given the following data from a tensile test. Show your
calculations for the following:
Tensile Stress
Modulus of Elasticity (Young’s Modulus)
Yield Strength
Percentage of elongation
Percentage of reduction in area
The following data were collected from a 12-mm-diameter test specimen of magnesium (l. = 30.00 mm): 250 Vielding 0.2% offset Load (N) 0 5,000 10,000 15,000 20,000 25,000 26,500 27,000 26,500 25,000 Gage Length (mm) 0.0000 0.0296 0.0592 0.0888 0.15 0.51 0.90 1.50 (maximum load) 2.10 Stress (MPa) oro...
Assignment 01 TOT Mechanical Properties of Materials 1. A tensile test specimen has a gage length = 50 mm and its cross-sectional area = 100 mm. The specimen yields at 48,000 N, and the corresponding gage length - 50.23 mm. This is the 0.2 ent yield point. The maximum load of 87,000 N is reached at a gage length 64.2 mm. Determine (a) yield strength, (b) modulus of elasticity, and (c) tensile strength. (d) If fracture occurs at a gage...
1.6 points) A tensile test specimen having a diameter of 10 mm and a gange length of 50 mm wa. tested to fracture. The stress-strain curve from the tension test is shown below. Labeling your points and showing the necessary steps, along with the corresponding calculations, find the following magnitudes: (a) Modulus of Elasticity, E = (b) Ultimate Strength = (e) Yield stress (0.2% offset method), (d) If the shear modulus of elasticity of the material is 28 GPa, determine...
question 6
of 25 mm is pulled in tension with a 44,500 N force producing only elastic detormation . What is oreonding strain and the length between the gage marks when subjected to this force? Given: elastic modulus of copper is 105 GPa. 5. A 10-mm diameter bar of 1040 carbon steel is subjected to a tensile load of 50,000 N, taking it beyond its yield point. Calculate the elastic recov removal of the tensile load. Given: elastic modulus of...
please show step by step solution for problem J
(J) For the sleeve and bushing of problem (I) if the pressure at the mating surface is 10,260 psi what is the tensile stress in the sleeve? Tensile stress = 46,470 psi Answer Box: Enter numerical values in italics t Data Inside radius of inner member Outside radius of inner memeber 0.0000 in b 0.5000 in 0.6250 in δ= 0.0019 in E0 = 3.00E+07 psi E- 300E+07 psi Outside radius of...
Most questions answered within 3 hours.
-
Luther Corporation
Consolidated Balance Sheet
December 31, 2019 and 2018 (in $ millions)
Assets
2019
2018...
asked 56 seconds from now -
(Expected rate of return and risk) Carter Inc. is evaluating a
security. Calculate the investment’s expected...
asked 2 hours ago -
What specific indicators can point to lack of progress for
African Americans in American society?
asked 3 hours ago -
1-The Electrons in a beam are moving at 2.7×108 m/s in an
electric field of 15000...
asked 3 hours ago -
A gas tank is a vertical cylinder. It has a radius of 1m, a
height of...
asked 4 hours ago -
Accent Software faces the following conditions. All of these
support Accent’s use of a market-penetration pricing...
asked 5 hours ago -
A mathematically inclined friend emails you the following
instructions: "Meet me in the cafeteria the first...
asked 5 hours ago -
A monopoly sells in two countries . The demand curves in the two
countries are p1...
asked 6 hours ago -
A .15kg rubber ball is bounced off a wall. Before hitting the
wall, the ball moves...
asked 7 hours ago -
A manufacturing company preparing to build a new plant is
considering three potential locations for it....
asked 7 hours ago -
B. If compound Y has approximately the same values of solubility
in toluene as compound X,...
asked 7 hours ago -
Oscar Inc. has inventory in Japan valued at 39,051,000 Yen one
year ago. One year ago...
asked 7 hours ago