How much voltage is dropped across the second resistor?
Homework Answers
Writing KVL loop equation
let current in R1 be I1 ,in R2 be I2 and in R3 be I3
I1=I2+I3
20-90=900I1+500I2=>-70=1400I2+900I3.................(1)
90=130I3-500I2...........................(2)
solving 1 and 2
I2=-0.1425A
I3=0.1439 A
I1=I2+I3=0.00149 A
Voltage drop acrossR2=I2*R2=71.25
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Find the voltage across the resistor in the circuit below 2 x
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a. 0.0018 V
b. 0.16 V
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URGENT!! PLEASE HELP! be clear and answer all questions
clearly!!
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