Question

The following reaction occurs within an erupting volcano: 2 H2S(g) + SO2(g) 3 S(s) + 2...

The following reaction occurs within an erupting volcano: 2 H2S(g) + SO2(g) 3 S(s) + 2 H2O(g) At 650 K, an equilibrium mixture contained H2S, SO2, and H2O at partial pressures of 1.17 atm, 1.07 atm, and 0.83 atm respectively. Calculate Kp at 650 K for the reaction

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Answer #1

The reaction is

2 H2S(g) + SO2(g) -------> 3 S(s) + 2 H2O(g)

Kp for the above reaction = (p H2O)^2 / (p SO2) (p H2S)^2

where

p H2O = Partial Pressure of H2O

p SO2 = Partial Pressure of SO2

p H2S = Partial Pressure of H2S

=> Kp = (0.83)^2 / (1.07) x (1.17)^2 = 0.47

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