Solution :
Given that,
Z/2 = Z0.005 = 2.576
Margin of error = E = Z/2
* (
/n)
= 2.576 * ( 11157 / 45
)
= 4284
At 99% confidence interval estimate of the population mean is,
- E < < + E
62400 - 4284 < < 62400 + 4284
( $ 58,116 <
< $ 66,684 )
salaries of 45 college graduate who took a statistics course in college have a mean of...
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