Question

Phosphorus reacts with oxygen to form diphosphorus pentoxide, P20g 2 P,O5(s) 4 P(s) 5 02(g) How many grams of P20g are formed when 7.39 g of phosphorus reacts with excess oxygen? Show the unit analysis used for the calculation by placing the correct components into the unit-factor slots 2 mol P2O 1 mol P 32.00 g O2 7.39 g P X X g P2Os 1 mol P2O 30.97 g P 4 mol P Answer Bank 141.94 g P2Os 1 mol O2 5 mol O

Answer 1

Consider following reaction. 4 P (3) + 50₂ (9) 2 Por 65). excess Give mass of Phosphorous (P) = 7.39 g. molecular mass of P2O5 = 141.94 glmol. molar mass of oxygen = 32.00 g/mol molar mass of phosphorus = 30.97 almol. :. The mass of P205 Produced will be. 7.39 gof p 1 mol. P 2 moles of P20s ~ 141.94 g. P205 30.97 g. pt 4 moles of p Imol of por. 2 = 7.39 X 30.97 x 4 141.94 1, 739 X 0.0323 x 0.5 X 141.94, = 16.9 g. = 0.169810² g. of P205