Question

lete this table if 10-fold dilutions are performed instead of 2-fold dilutions. Cuvette Concentration Dilution fronm 6) Compl Fold Dilution original 0 1M 10 1:10 100 4

Answer 1

here at each cuvette dilution added is by the factor of 10

cuvette 2

Dilution from original is 1:10

then concentration=initial concentration*dilution (dilution=1/fold dilution)

=1M*1/10

=0.1M

cuvette 3

Dilution from original is 1:100

then concentration=initial concentration*dilution (dilution=1/fold dilution)

=1M*1/100

=0.01M

cuvette 4

fold dilution=1000

dilution from original is 1:1000

then concentration=initial concentration*dilution (dilution=1/fold dilution)

=1M*1/1000

=0.001M

cuvette 5

fold dilution=10000

lution from original is 1:10000

then concentration=initial concentration*dilution (dilution=1/fold dilution)

=1M*1/10000

=0.0001M