Question

Partner: Name: Date Chem 180L Titration: Report Sheet Data Table Flask #1 Flask 2 Flask #3 Mass of KHP 0.526 g 0.434 g 0.492 g Final buret reading 50.00 mL 35.55 ml 19.85 ml Initial buret reading 35.55 mL 19.85 mL 7.50 mL Volume of NaOH used Moles of acid Moles of base used Concentration of NaOH Average concentration of NaOH Show calculation set ups below for Flask #1:

Answer 1

Flask#1 :

Volume of NaOH used = 50.00-35.55 = 14.45 ml

Moles of acid = mass/molar mass= 0.526g/204.22 g/mol = 0.0025756537 mol

Moles of base used = 0.0025756537 mol

Concentration of NaOH =

0.0025756537 mol/0.01445L= 0.17825 M

Flask#2:

Volume of NaOH used = 35.55-19.85= 17.50ml

Moles of acid = 0.434g/204.22g/mol

= 0.0021251591mol

Moles of base used= 0.0021251591mol

Concentration of NaOH = 0.12144 M

Flask#3:

Volume of NaOH used = 19.85-7.5= 12.35ml

Mass of acid = 0.492g/204.22g/mol

= 0.0024091666 mol

Moles of base used = 0.0024091666 mol

Concentration of NaOH =

0.0024091666 mol/0.01235L = 0.1951 M

Average concentration of NaOH = 0.165 M