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A uniform bar of mass m 5.1kg is supported by a pivot at the bottom and a horizontal rope. The bar is length L = 2.5m and the

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m=5.1kg, L=205m, d=10975m, T=17.8N T int co Idoso . mg for rotahonal esm: Tx dcose= mg + Ļ Sino 3 tane=2Td = 2x1768x10975 501

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