est 1 Version A Page 5 of 12 6. An object of mass 0.115 kg moves...

Question

Question

Answer 1

Answer #1

a) initial kinetic energy = 0.5mu^2 = 0.5*0.115*0^2 = 0

b) final kinetic energy = 0.5mv^2 = 0.5*0.115*25^2 = 35.94 J

c) according to work energy theorem

work done = change in kinetic energy

= 35.94 - 0

= 35.94 J

Answer 2

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