Plz i feel like i am getting this wrong! by the way my answer is dihybrid....
Homework Answers
Answer: d) Dihybrid
The cross is between flies which differ in two traits, body color and wing type. Dihybrid cross is also characterized as a cross between two different lines which differ in two observable traits. Due to this reason the correct answer is dihybrid cross. From the given number of offspring and deduced ratio it cannot be monohybrid cross or test cross involving one gene. It cannot be a test cross involving two genes because the genotype of the phenotypically dominant individual is already known which means that it is a dihybrid cross.
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Plz i feel like i am getting this wrong! by the way my answer is
dihybrid.......
o a phenotypically wildtype fruit fly of unknown origin to a fly homozygou #1) and vg (vestigial wings mutations the following offspring were obtained: pts) In a cross of a phenotypicall ck body...
o a phenotypically wildtype fruit fly of unknown origin to a fly homozygou #1) and vg (vestigial wings mutations the following offspring were obtained: pts) In a cross of a phenotypicall ck body, fr . wildtype - 12 black body, normal wings -34 normal body, vestigial wings 38 black body, vestigial wings - 16 a. Are genes b and vg linked or not? what would you have seen if the opposite were true? b. If they are not linked, prove...
feel like I did these wrong numbers too high on first problem? how do you know...
feel like I did these wrong
numbers too high on first problem?
how do you know which gene is in the middle?
thank you.
Question #1 . To determine the)rder of three genes, a cross was set up fly was homozygous for three mutations - cherub wings (cw), black body (b), and cinnabar eyes cn). The other fly was homozygous wild type for all three genes (cw b cn). F1 females from the cross were test-crossed with cherub, black, and...
In Drosophila, b+ is the allele for normal body color and at the same gene b...
In Drosophila, b+ is the allele for normal body color and at the same gene b is the allele for black body color. A second gene controls wing shape. The shape can be either normal (vg+) or vestigial (vg). A cross is made between a homozygous wild type fly and fly with black body and vestigial wings. The offspring were then mated to black body, vestigial winged flies. The following segregation ratio was observed: Phenotype # Observed Wild Type (normal,...
2. The lubber grasshopper is a very large grasshopper, and is black with red and yellow...
2. The lubber grasshopper is a very large grasshopper, and is black with red and yellow stripes. Assume that red stripes are expressed from the homozygous RR genotype, yellow stripes from the homozygous rr genotype, and both from the heterozygous genotype. A. If two heterozygous grasshoppers were crossed, what would be the genotypic ratio of the F1 generation (RR:Rr:rr)? Fill in the Punnett square. B. What genotypes would be produced by crossing a grasshopper with both color stripes and one...
Please show work. 2. You mate a female fly with a black body, purple eyes, and...
Please show work.
2. You mate a female fly with a black body, purple eyes, and vestigial wing size to a wild- type male. These three alleles are located on chromosome II (autosome) in Drosophila. You testcross one of the Fi females to a male with all three mutations and record the results from the testcross in following table. Phenotype # of each phenotype Body color eye color wing size red red red red 900 le normal vestigial 90 50...
Pre-lecture lesson 2.12: Linkage and Gene Mapping You are charged with testing whether 2 different genes...
Pre-lecture lesson 2.12: Linkage and Gene Mapping You are charged with testing whether 2 different genes are independently assorting during meiosis in Drosophila melanogaster, the fruit fly The 2 genes you will be observing for this experiment are: Black: a recessive allele of this gene (b) results in a dark body color (somewhat similar to ebony, but a richer dark coloration that is less ashen-colored). The dominant allele for this gone (B) produces wild type body color Vestigial: a recessive...
all of them please Question 10 (1 point) In Drosophila, the mutant black (b) has a...
all of them please
Question 10 (1 point) In Drosophila, the mutant black (b) has a black body and the wild-type (b+) has a gray body; the mutant vestigial (v) has wings that are short and crumpled compared the long wild-type wings (V+). These genes are linked and are located on the X- chromosome. A cross between a female fly and a black, vestigial winged male fly produced the following progeny: gray (b+), normal (v+) 20 gray (b+), vestigial (v)...
Please answer the following two questions. Show all your work. Thanks in advance. 9. In Drosophila...
Please answer the following two questions. Show all your work. Thanks in advance. 9. In Drosophila yellow body color is caused by a sex-linked recessive allele and brown eye color is an autosomal recessive trait. A phenotypically normal female fly, heterozygous for both genes, is crossed to a male with normal body color and brown eyes. What proportion of their offspring should have yellow body color and brown eyes? A) 1/16 B) 1/8 C) 1/4 D) 3/16 E) 3/8 ANSWER:...
16. Use the following information to answer the questions below. Drosophila (fruit flies) usually have long...
16. Use the following information to answer the questions below. Drosophila (fruit flies) usually have long wings (+) but mutations in two different genes can result in bent wings (bt) or vestigial wings (vg). If a homozygous bent wing fly is mated with a homozygous vestigial wing fly, which of the following offspring would you expect? a. 1/2 bent and vestigial to 1/2 normal b. 1/2 bent and 1/2 vestigial flies c. 3/4 bent to 1/4 vestigial ratio d. all...
The solutions are given, but could you please help me by providing the steps to get...
The solutions are given, but could you please help me by
providing the steps to get to the answer. I would like to be able
to understand the way to get to the answers given. Thank you!
Please show as much work as possible so I can follow along. Thank
you!
3. You have been playing craps at Las Vegas and suspect that the dice are loaded. You decide to perform an experiment using a single die to determine how...
o a phenotypically wildtype fruit fly of unknown origin to a fly homozygou #1) and vg (vestigial wings mutations the following offspring were obtained: pts) In a cross of a phenotypicall ck body, fr . wildtype - 12 black body, normal wings -34 normal body, vestigial wings 38 black body, vestigial wings - 16 a. Are genes b and vg linked or not? what would you have seen if the opposite were true? b. If they are not linked, prove...
feel like I did these wrong
numbers too high on first problem?
how do you know which gene is in the middle?
thank you.
Question #1 . To determine the)rder of three genes, a cross was set up fly was homozygous for three mutations - cherub wings (cw), black body (b), and cinnabar eyes cn). The other fly was homozygous wild type for all three genes (cw b cn). F1 females from the cross were test-crossed with cherub, black, and...
In Drosophila, b+ is the allele for normal body color and at the same gene b is the allele for black body color. A second gene controls wing shape. The shape can be either normal (vg+) or vestigial (vg). A cross is made between a homozygous wild type fly and fly with black body and vestigial wings. The offspring were then mated to black body, vestigial winged flies. The following segregation ratio was observed: Phenotype # Observed Wild Type (normal,...
2. The lubber grasshopper is a very large grasshopper, and is black with red and yellow stripes. Assume that red stripes are expressed from the homozygous RR genotype, yellow stripes from the homozygous rr genotype, and both from the heterozygous genotype. A. If two heterozygous grasshoppers were crossed, what would be the genotypic ratio of the F1 generation (RR:Rr:rr)? Fill in the Punnett square. B. What genotypes would be produced by crossing a grasshopper with both color stripes and one...
Please show work.
2. You mate a female fly with a black body, purple eyes, and vestigial wing size to a wild- type male. These three alleles are located on chromosome II (autosome) in Drosophila. You testcross one of the Fi females to a male with all three mutations and record the results from the testcross in following table. Phenotype # of each phenotype Body color eye color wing size red red red red 900 le normal vestigial 90 50...
Pre-lecture lesson 2.12: Linkage and Gene Mapping You are charged with testing whether 2 different genes are independently assorting during meiosis in Drosophila melanogaster, the fruit fly The 2 genes you will be observing for this experiment are: Black: a recessive allele of this gene (b) results in a dark body color (somewhat similar to ebony, but a richer dark coloration that is less ashen-colored). The dominant allele for this gone (B) produces wild type body color Vestigial: a recessive...
all of them please
Question 10 (1 point) In Drosophila, the mutant black (b) has a black body and the wild-type (b+) has a gray body; the mutant vestigial (v) has wings that are short and crumpled compared the long wild-type wings (V+). These genes are linked and are located on the X- chromosome. A cross between a female fly and a black, vestigial winged male fly produced the following progeny: gray (b+), normal (v+) 20 gray (b+), vestigial (v)...
The solutions are given, but could you please help me by
providing the steps to get to the answer. I would like to be able
to understand the way to get to the answers given. Thank you!
Please show as much work as possible so I can follow along. Thank
you!
3. You have been playing craps at Las Vegas and suspect that the dice are loaded. You decide to perform an experiment using a single die to determine how...
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