(Figure 1) shows a pV diagram for a heat engine that uses 1.40 moles of an...

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(Figure 1) shows a pV diagram for a heat engine that uses 1.40 moles of an ideal gas. The internal energy of the gas changes by the following amounts: ΔUa→b=+4040J, ΔUb→c=−4848J, ΔUc→d=−808J, and ΔUd→a=+1616J

p (atm) 1.0 1. 0 Ί 3 01 5.0 7.0 V(L). 2o 4o 6.0

How much heat is ejected by the gas per cycle? Express your answer in joules to three significant figures.

How much work does this engine do each cycle? Express your answer in joules to three significant figures.

What is the thermal efficiency of the engine? Express your answer as a percentage to two significant figures.

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Answer 1

Answer #1

Workdone in all process

Wab = P(V2 - V1) = 5×105×(6 - 2)×10-3 =2000 J

Wbc = 0 (because constant volume process)

Wcd = P(V2 - V1) = 1×105×(2 - 6)×10-3= - 400 J

Wda = 0 ( because constant volume process)

So heat transfered

Qab = Uab + Wab = 4040 + 2000 = 6040 J

Qbc = Ubc + Wbc = - 4848 + 0 = - 4848 J

Qcd = Ucd + Wcd = - 808 - 400 = - 1208 J

Qda = Uda + Wda = 1616 + 0 = 1616 J

Efficiency of the cycle = net workdone/heat given

Net work done = 2000 - 400 = 1600 J

Heat given = 6040 + 1616 = 7656 J

Efficiency = 1600/7656 = 0.2089

So Efficiency = 20.89 %

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Answer 2

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