Question

0 UO -- 3) Write an SOP expression for the following Truth Table. B C D 0 0 0 0 0 1 10 0 1 0 0 1 0 1 1 1 0 10 1 0 0 0 0 1 1 1 0 0 11 1 0 0 -- 400--0-------0-70 - 1 0 -- Draw the circuit Simplify using Boolean Algebra Simplify using a Karnaugh Map

Answer 1

We have to write an SOP expression for the given truth table, A B C DX 0 0 0 0 0 0 0 0 1 0 0 0 10 0 0 1 1 1 0 000 0 0 1 1 0 1 100 1 0 0 0 1 0 101 1 1 0 0 0 i i 100 X = Em 2, 3, 5, 8, 9, 10, 11, 13) روذ Sof eps Men x = ĀBCD + Ā B CD + Ā B C D TAB CD TABCO + Авст+ ALCD+ ввер the circuit for above Now we have to draw CS seexpression CamScanner

A-D D AD A- B -- - A- X= Zn(a 3,5,8,9, 10,11,13) B-DO D Dol DUDUQCJA is the circuit for Above sop expression without simplification. Now we can simplify the expression using s Boolean algebra and Karnaugh map CamScanner

SOP expression ill, x = Ã B C. Ď t he CD & Ã BED 4 A B C D 4 ABCD FABCD + ABCD + ABCD => x = Ā B CCD+) + ñ BTD + AB (CD+CD+CD+ 4 ABCD => x = Ā B C + Ā B C D & AŠ (CCB+o) + c(BD)) + ABTD -> x= ABC +A+A) BCD + AB (EFC) ( By Boolean i algebra, ū+x= i7 = x= = x = >> X = Ā BC + B C D TAB B ( ÃC+A) + B C D B CĀta) (A+c) +B C D [": AB+c=(A+)6+ 1 => x = B(A+c) +BCD = x= A B + BC + B C D Now above is simplified Csalge bir anner expression using Boolean Iris Scanned with

- Now below is by using t-map Now simplied expression is, X = Ā B C + BCD + AB Now the circuit by using simplied expression obtained by km ap us AD B TIL 19 Circuit by using simplified expression Obtained by boolean algebra is x= A 8 + 8c + BED Scanned with CamScanPer