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In an experiment, two students combined 22.5 mL of 0.200 M HN3 with NaOH. What was the pH when 12.5 mL of 0.150M NaOH had bee
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Answer #1

Compound. I 50. LUDM Compound-I [NH₃] VN Hz 0.00L mole of NH₃ = 0. 20 ml x 0.Dorsh = 4.5X10 mal [ Nach] 0.150 ml Voor = 12.5m

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