F = qE = 1.6 x 10^-19 x 75 = 1.2 x 10^-17 N
acceleration = F/m = 1.318 x 10^13 m/s^2
time to reach the other plate =
S = .5 x a x t^2
3 x 10^-3 = .5 x 1.318 x 10^13 x t^2
t = 2.13 x 10^-8 s
velocity perpendicular to the plate = at = 1.318 x 10^13 x 2.13 x 10^-8
v = 2.8 x 10^5 m/s
total velocity = root (2.8 x 10^5^2 + 5.5 x 10^4 ^2)
= 2.8 x 10^6 m/s
An electron traveling at a speed of 5.50*10^4 m/s enter a region midway between two parallel...
As shown in the figure, an electron is fired with a speed of 3.59 × 106 m/s through a hole in one of the two parallel plates and into the region between the plates separated by a distance of 0.24 m. There is a magnetic field in the region between the plates and, as shown, it is directed into the plane of the page (perpendicular to the velocity of the electron). Determine the magnitude of the magnetic field so that...
An electron is launched with a constant horizontal speed of 2.0times 10+m/s into a region between two large parallel plated. The magnitude of the constant electric field between the plates is 50,000N/C, Calculate the distance that the electron will be deflected by the Electric field.
A proton moving at 3.0 106 m/s passes into the region between two parallel conductors. The region between the plates has a constant electric field pointing to the right of magnitude 2.0 x 104 N/C. a) what acceleration does the proton experience between the plates? b) if the plates were 3 cm apart what is the speed of the proton as it exits the plates?
A proton moving at v0 = 1.70 ✕
106 m/s enters the region between two parallel plates
with charge densities of magnitude σ = 2.60 ✕
10−9 C/m2 (see the figure below).
A uniform electric field is produced by two charged horizontal
plates, each of length d, where the positive plate is
above the negative plate. The leftmost side of each plate is at
horizontal position x = 0. The upper plate has charge
density +σ and the lower plate...
An electron travels with speed 9.0×106 m/s between the two parallel charged plates shown in the figure. The plates are separated by 1.0 cm and are charged by a 200 V battery. (Figure 1) What magnetic field strength will allow the electron to pass between the plates without being deflected?
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A proton traveling at v= 4.65 x 10° m/s to the right enters the region between two parallel charged plates separated by a distance d = 5.09 cm that also contains a uniform magnetic field out of the page of field strength B = 8.47 ut. a What does the potential difference across the plates have to be for the proton to continue traveling at constant velocity? Express your answer using two decimal places. Your answer should be in V.
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A proton enters a parallel-plate capacitor traveling to the right at a speed of 1.276 x 10-5 m/s, as shown in the figure. The distance between the two plates is 1.59 cm. The proton enters the capacitor halfway between the top plate and the bottom plate; that is, a distance r = 0.795 cm from each plate, as shown in the figure. The capacitor has a 2.75 x 10-4 N/C uniform electric field between the plates that points downward from...