Question

Experiment 7, Analysis of KHP by titration with NaOH Wright College, Department of Physical Science and Engineering In this experiment, you will determine the amount (percent) of potassium hydrogen phthalate (KHP) that is in an impure sample. You will determine the percent of KHP via titration using NOH with known inolarity. The reaction will follow, KHCgH00, (aq) + NaOH (aq) ---------> KNaCHO, (aq) + H20 (I) At the end point, the moles of KHP will equal the moles of NaOH. You will use phenolphthalein as the indicator, The end point of the reaction will be a light pink solution color. PRELAB ASSIGNMENT gre pune I will see a light pink color 1. How will you know the reactie is over? If 2. About how much KHP will be used in the titration? betrea 1.009 out 1.209. 3. Which 3 substances go into the 250 ml Erlenmeyer flask for the titration? KHP; ocionizel o , anel ole to mole ratio in the reaction or KHP and NaOH? pheadphth mein XOXO XOXO SAXXX 5. What solution goes into the buret? 2 NaOH XXC XXXX PROCEDURE All waste can be put down the sink. SOKAKUU 1. Record the KHP unknown number and the concentration of the NaOH solution in the report sheet. 2 2. Boil about 400 mL of deionized H2O for about 5 minutes and let cool. This procedure will remove any dissolve carbon dioxide that is naturally found in water, Carbon dioxide in water produces carbonic acid (HCC). an unwanted acid LE 3. Using weighing paper, weigh a sample of your impure KHP that is betwo 1.20 grams and record the exact mass. 4. Add the KHP to a 250 m. Erlenmeyer flask along with 100 mL of deioniz of phenolphthalein indicator. Use your glass stirring rod to completely dissol it to convert the moles of KHP to w your calculation below and record 5. Obtain about 200 mL of NaOH solution. Use about 25 mL of the NaOH S a buret. Don't forget to release some of the NaOll solution out the bottom of waste, put it down the sink. 6 Fill your hunt un olnu

please help me speciqlly with 11. 12. 13. 14  

Answer 1

NaOH vol used = 16.40-0,15 = 16.25 mL -0.01625L - Moles of NaOH = Molarity xrof. used in L = 0.1014 mol/, x 0.016252=0.00165 moles from balanced chemical eq. it is clear that no. of moles of NaOH used = moles of kHP present in the sample -0.00165 moles Gurams of KHP in sample = moles x molas mass of = 0.00165 mol x 204.22gmol = 0.33659 > Percent KHP in sample= mass of kHP calculate you given mass of KAP KHP - 0.3365 g xloo = 131.45%) 7.07g Similarly can be calculated for other can be calo ctrials