Homework Answers
K1 = [N2][O2]/[NO]^2
= 1.0*10^30
K2 = [NOBr]^2 / [N2][O2][Br2]
= 2.0*10^-27
The required equation is:
K = [NO]^2[Br2]/[NOBr]^2
= ([NO]^2 / [N2][O2]) * ([N2][O2][Br2] / [NOBr]^2)
= (1/K1) * (1/K2)
= 1/(K1*K2)
= 1/(1.0*10^30 * 2.0*10^-27)
= 1/(2.0*10^3)
= 5.0*10^-4
Answer: d
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z 5. Consider the following equilibria in aqueous solution at room temperature: 2NO(g) = N2(g) +...
The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) =...
The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) = 2NO(g) Ke = 4.3 x 10-25 2NO(g) + O2(g) + 2NO:(8) K-6.4 x 10 Determine the values of the equilibrium constants for the following equations at the same temperature: (a) 4NO(g) = N2(g) + 2NO:(g) x 10 (b) 4NO:() = 2N:(0) + 40:(8) x 10 (c) 2NO(g) + 2NO3(g) = 30:(g) + 2N:(g) x 10
The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) =...
The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) = 2NO(g) Ke = 4.3 x 10-25 2NO(g) + O2(g) + 2NO:(8) K-6.4 x 10 Determine the values of the equilibrium constants for the following equations at the same temperature: (a) 4NO(g) = N2(g) + 2NO:(g) x 10 (b) 4NO:() = 2N:(0) + 40:(8) x 10 (c) 2NO(g) + 2NO3(g) = 30:(g) + 2N:(g) x 10
[Review Topics) [References) At a particular temperature, K = 6.8 x 10-7 for the following balanced...
[Review Topics) [References) At a particular temperature, K = 6.8 x 10-7 for the following balanced reaction: 2NOBr(g) → 2NO(g) + Br2(g) In an experiment in which 1.0 mol of NOBr is placed in a 2.0-L vessel, what are the equilibrium concentrations of all gases? NOBr] M [NO] = M ET [Br2] M Submit Answer Retry Entire Group 9 more group attempts remaining
5-10 The data below refer to the following reaction: 2NO(g) + Brz(g) 2NOBr(g) [NO] 2.5 [Brz] Concentration (M) Initial...
5-10 The data below refer to the following reaction: 2NO(g) + Brz(g) 2NOBr(g) [NO] 2.5 [Brz] Concentration (M) Initial Equilibrium [NOBr] 5.0 1.0 2.0 Calculate Kc Ans: 0.12 5-11 The AG of atomic oxygen is 230.1 kJ/mol. Determine the equilibrium constant for the following reaction at standard thermodynamic conditions: O2(g) 52 0(g). A) 4.7 x 10-41 B) 2.3 x 10-61 C) 2.1 x 10-81 D) 2.1 x 1040 E) 4.5 x 1080
Write the expressions for Kp for the following reactions: 1. a) 2NH3(g) + Co2(g) N2CH40(s) +...
Write the expressions for Kp for the following reactions: 1. a) 2NH3(g) + Co2(g) N2CH40(s) + H20 (I) b) CuO (s) + H2(g) Cu(l)+H20 (g) 2. At room temperature, a 1.5 L flask contains 3.0 moles of Cl, 0.5 mole of NOCI, and 4.0x10 mole of NO. Calculate Ke at this temperature for the following reaction: 2NO (g) + Cl2(g) 2NOCİ (g) 0.00245 M, does this represent a system at M, [No] 0.2 M and [Ch] If [NOCI] 2.0x 10...
Consider the following reactions at some temperature: 2NOCI(g) � 2NO(g) + Cl2 (g) K = 1.6...
Consider the following reactions at some temperature: 2NOCI(g) � 2NO(g) + Cl2 (g) K = 1.6 X 10-5 2NO(g) � N2 (g) + 02 (g) K = 1 X 1031 For each reaction, assume some quantities of the reactants were placed in separate containers and allowed to come to equilibrium. Describe the relative amounts of reactants and products that would be present at equilibrium. At equilibrium, which is faster, the forward or reverse reaction in each case?
Consider the following reaction where Kc = 154 at 298 K: 2NO(g) + Br2(g) 2NOBr(g) A...
Consider the following reaction where Kc = 154 at 298 K: 2NO(g) + Br2(g) 2NOBr(g) A reaction mixture was found to contain 2.42×10-2 moles of NO(g), 4.38×10-2 moles of Br2(g) and 9.68×10-2 moles of NOBr(g), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: 1. In order to reach equilibrium NOBr(g) must be produced. 2. In order to reach equilibrium Kc must decrease. 3. In order to reach equilibrium NO must be produced....
5. Given the following chemical equilibria, N2(g) + O2(g) = 2 NO(g) N2(g) + 3 H2(g)...
5. Given the following chemical equilibria, N2(g) + O2(g) = 2 NO(g) N2(g) + 3 H2(g) = 2 NH3(g) H2(g) + 1/2 O2(g) =H2O(g) Determine the method used to calculate the equilibrium constant for the reaction below. 4 NH3(g) + 5 O2(g) = 4 NO(g) + 6 H2O(g) K
Consider the following reaction where K. = 154 at 298 K: 2NO(g) + Br2(g) = 2NOBr(g)...
Consider the following reaction where K. = 154 at 298 K: 2NO(g) + Br2(g) = 2NOBr(g) A reaction mixture was found to contain 2.86x10-2 moles of NO(g), 3.93x10-2 moles of Br2(g) and 8.83x10-2 moles of NOBr(g), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: 1. In order to reach equilibrium NOBr(g) must be consumed. 2. In order to reach equilibrium K, must increase. 3. In order to reach equilibrium NO must be...
3. Consider a room temperature, 100mL aqueous solution saturated with the ionic compound beryllium hydroxide Be(OH)2...
3. Consider a room temperature, 100mL aqueous solution saturated with the ionic compound beryllium hydroxide Be(OH)2 due to the addition of 10g of Be(OH)2; MM-43.02 g-mol-1. KsP-2.0 x10-8 Use this provided information to calculate the pH of this saturated solution. Hints: Due to the low solubility product, very little of this compound actually dissolves in H20. Go ahead and assume all activity coefficients are equal to 1.0 for this problem. This seems like a good opportunity to apply the ICE...
The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) = 2NO(g) Ke = 4.3 x 10-25 2NO(g) + O2(g) + 2NO:(8) K-6.4 x 10 Determine the values of the equilibrium constants for the following equations at the same temperature: (a) 4NO(g) = N2(g) + 2NO:(g) x 10 (b) 4NO:() = 2N:(0) + 40:(8) x 10 (c) 2NO(g) + 2NO3(g) = 30:(g) + 2N:(g) x 10
The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) = 2NO(g) Ke = 4.3 x 10-25 2NO(g) + O2(g) + 2NO:(8) K-6.4 x 10 Determine the values of the equilibrium constants for the following equations at the same temperature: (a) 4NO(g) = N2(g) + 2NO:(g) x 10 (b) 4NO:() = 2N:(0) + 40:(8) x 10 (c) 2NO(g) + 2NO3(g) = 30:(g) + 2N:(g) x 10
[Review Topics) [References) At a particular temperature, K = 6.8 x 10-7 for the following balanced reaction: 2NOBr(g) → 2NO(g) + Br2(g) In an experiment in which 1.0 mol of NOBr is placed in a 2.0-L vessel, what are the equilibrium concentrations of all gases? NOBr] M [NO] = M ET [Br2] M Submit Answer Retry Entire Group 9 more group attempts remaining
5-10 The data below refer to the following reaction: 2NO(g) + Brz(g) 2NOBr(g) [NO] 2.5 [Brz] Concentration (M) Initial Equilibrium [NOBr] 5.0 1.0 2.0 Calculate Kc Ans: 0.12 5-11 The AG of atomic oxygen is 230.1 kJ/mol. Determine the equilibrium constant for the following reaction at standard thermodynamic conditions: O2(g) 52 0(g). A) 4.7 x 10-41 B) 2.3 x 10-61 C) 2.1 x 10-81 D) 2.1 x 1040 E) 4.5 x 1080
Write the expressions for Kp for the following reactions: 1. a) 2NH3(g) + Co2(g) N2CH40(s) + H20 (I) b) CuO (s) + H2(g) Cu(l)+H20 (g) 2. At room temperature, a 1.5 L flask contains 3.0 moles of Cl, 0.5 mole of NOCI, and 4.0x10 mole of NO. Calculate Ke at this temperature for the following reaction: 2NO (g) + Cl2(g) 2NOCİ (g) 0.00245 M, does this represent a system at M, [No] 0.2 M and [Ch] If [NOCI] 2.0x 10...
5. Given the following chemical equilibria, N2(g) + O2(g) = 2 NO(g) N2(g) + 3 H2(g) = 2 NH3(g) H2(g) + 1/2 O2(g) =H2O(g) Determine the method used to calculate the equilibrium constant for the reaction below. 4 NH3(g) + 5 O2(g) = 4 NO(g) + 6 H2O(g) K
Consider the following reaction where K. = 154 at 298 K: 2NO(g) + Br2(g) = 2NOBr(g) A reaction mixture was found to contain 2.86x10-2 moles of NO(g), 3.93x10-2 moles of Br2(g) and 8.83x10-2 moles of NOBr(g), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: 1. In order to reach equilibrium NOBr(g) must be consumed. 2. In order to reach equilibrium K, must increase. 3. In order to reach equilibrium NO must be...
3. Consider a room temperature, 100mL aqueous solution saturated with the ionic compound beryllium hydroxide Be(OH)2 due to the addition of 10g of Be(OH)2; MM-43.02 g-mol-1. KsP-2.0 x10-8 Use this provided information to calculate the pH of this saturated solution. Hints: Due to the low solubility product, very little of this compound actually dissolves in H20. Go ahead and assume all activity coefficients are equal to 1.0 for this problem. This seems like a good opportunity to apply the ICE...
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