Question

il Sprint 15%D 8:22 PM 7 of 17 Done Using line notation, write down what the following picture is describing Anode Cathode br the photo with the graphic is question 6. doesnt need to be answred. just need the concentration of Zn2+ thankyou upvote ofcourse
At what concentration of Zn2+ will the situation in question 6 become nonspontaneous if [Cu2+] = 0.1M? B IV AA- IE: - DO VE 1
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Answer #1

Anode : Zn(s) = Zn2+(aq) + 2e E° = 0.76

Cathode: Cu2+(aq) +2e = Cu(s) E° = 0.34

E°cell = 0.76 + 0.34 = 1.10 V

Line notation--

Zn(s)|Zn2+(aq)||Cu2+(aq)|Cu(s)

Cell become non spontaneous when E<0

So, Ecell = E°cell - (0.059/n)log(Zn2+/Cu2+)

= Ecell = 1.10 - (0.059/2)log(Zn2+/0.1) < 0

=> [Zn2+] > 1.94*10^36 M

So, concentration of Zn2+ should be greater than 1.94*10^36 to make the cell reaction non spontaneous.

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