To balance a chemical equation count the number of atoms of each element on the both sides of a reaction and equalise them by adding suitable coefficients.
Balanced equation for this reaction is,
4NH3 + 3O2 ------------> 2N2 + 6H2O
4 moles of NH3 gives 2 moles of N2.
1 mole of NH3 will give 2/4 moles of N2 i.e. 0.5 moles of N2.
Number of moles = Mass/molar mass
Molar mass of NH3 =17.03 g/mol
Moles of NH3 = 38.7/17.03
= 2.27 moles
Moles of N2 formed = 2.27 × 0.5
= 1.14 moles N2.
Molar mass of N2 = 28.01 g/mol
Mass of N2 formed = 28.01 g/mol × 1.14 mol
= 31.9 grams.
Theoretical yield = 31.9 grams.
6. Percent yield = (actual yield/theoretical yield) × 100
Percent yield = (17.9/31.9)×100
= 56.11 %
Percent yield = 56.11 %
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