using the dilution law
M1V1 = M2V2
M1 = 0.0250 M , V1 = 0.050 L
M2 = ? , V2 = 0.250 L
substituting the values in the equation
M2 = M1V1 / V2
M2 = 0.0250 * 0.05 / 0.250
M2 = 0.00500M
answer => 0.00500 M
Determine the final concentration of sucrose after 50,00 mL of a 0.0250 M sucrose solution is...
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The concentration of a solution after dilution can be found
by:
where M1 is the concentrated solution (in
this lab, 0.400 M), and V1 is the volume of the
concentrated solution placed in the test tube. The
V2 is the total volume of
concentrated solution plus water added, and M2
is the concentration of the solution after diluting.
Tube 1 has 2.00 mL of the 0.400 M Ni2+ solution and
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If 45.0 ml of 0.25 M sodium chloride solution is diluted to a
final volume of 170.0 ml what is the concentration of the new
solution ?
I know the answer is A but I don’t know how to get to the
right answer :(
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