We have 0.10 M HPO42-
It can form buffer if we add PO43- which is conjugate base of
HPO42-
So, option 1 and 2 are correct
It can form buffer if we add H2PO4— which is acid of
HPO42-
So, option 4 is correct
Answer: option 3
A 0.10 M solution of Na2HPO4 could be made a buffer solution with all of the...
Part A Calculate the pH of a 0.10 M solution of barium hydroxide, Ba(OH)2 Express your answer numerically using two decimal places. View Available Hint(s) 20 A20 0 2 ? pH Submit Part B Calculate the pH of a 0.10 M solution of NaOH Express your answer numerically using two decimal places. View Available Hint(s) VO ALDO ? Submit Part Part B ve a Calculate the pH of a 0.10 M solution of NaOH. Express your answer numerically using two...
a) What are the concentrations of Na2HPO4 and NaH2PO4 in a 0.30 M phosphate buffer solution pH 7.0? Use pKa 6.82 b) Describe how you would prepare 250 mL of the buffer in part (a) given that you have available to you a 1.0 M stock solution of NaH2PO4 and solid Na2HPO4(FW 141.96 g/mol). Provide your answer in milliliters of NaH2PO4 and grams of Na2HPO4. c) Suppose you use 100 ml of this buffer in an experiment and 0.003 mol...
A 0.250 L buffer is made of 0.350 M [NaH2Po4] and 0.255M [Na2HPO4]. a. what is pH of this buffer? b. What is pH of this buffer after 0.012 mols of HCl is added? Please show work and all steps!!!!
Calculate the pH of a 0.10 M solution of NaOH. Express your answer numerically using two decimal places. ► View Available Hint(s) IVO AQ O ? pH = Submit Part C Calculate the pH of a 0.10 M solution of hydrazine, NH K! for hydrazine is 1.3 x 10-6 Express your answer numerically using two decimal places! View Available Hint(s) 70 AED + O2 ? pH =
You are instructed to create 400. mL of a 0.40 M phosphate buffer with a pH of 6.4. You have phosphoric acid and the sodium salts NaH2PO4, Na2HPO4, and Na3PO4 available. (Enter all numerical answers to three significant figures.) H3PO4(s) + H2O(l) H3O+(aq) + H2PO4−(aq) Ka1 = 6.9 ✕ 10−3 H2PO4−(aq) + H2O(l) H3O+(aq) + HPO42−(aq) Ka2 = 6.2 ✕ 10−8 HPO42−(aq) + H2O(l) H3O+(aq) + PO43−(aq) Ka3 = 4.8 ✕ 10−13 Which of the available chemicals will you use...
Part B . Calculate the pH of a 0.10 M solution of hypochlorous acid, HOCI. K. of HOCI is 3.5 x 10-8 at 25°C. Express your answer numerically using two decimal places. View Available Hint(s) IVO | ΑΣφ pH Submit Part Calculate the pH of a 0.10 M solution of HCI. Express your answer numerically using two decimal places. View Available Hint(s) . AE pH OF Submit BERARE Provide Feedback
Part A What is the pH of a buffer solution containing 0.10 M H2CO3 and 0.10 M NaHCO3 ? Express your answer using two decimal places pH- Submit Request Answer Part B ,co, and 0.053 M NaHCO? What is the pH of a buffer solution containing 0.25 M Express your answer using two decimal places. pH - Request Answer Submit
You are instructed to create 400. mL of a 0.39 M phosphate buffer with a pH of 6.2. You have phosphoric acid and the sodium salts NaH2PO4, Na2HPO4, and Na3PO4 available. (Enter all numerical answers to three significant figures.) H3PO4(s) + H20(I) =H30+ (aq) + H2PO4 (aq) Kai = 6.9x10-3 H2PO4 (aq) + H20(1) =H30+ (aq) + HPO42-(aq) Ka2 = 6.2 x 10-8 HPO42-(aq) + H20(1) = H30+(aq) + PO43-(aq) Ka3 = 4.8x10-13 Which of the available chemicals will you...
You are instructed to create 400. mL of a 0.39 M phosphate buffer with a pH of 6.2. You have phosphoric acid and the sodium salts NaH2PO4, Na2HPO4, and Na3PO4 available. (Enter all numerical answers to three significant figures.) H3PO4(s) + H2O(l) = H30+ (aq) + H2P04 (aq) Kai = 6.9 x 10-3 H2PO4 (aq) + H20(1) =H30+ (aq) + HPO42-(aq) Ka2 = 6.2 x 10-8 HPO42-(aq) + H20(I) = H30+(aq) + PO43-(aq) Ka3 = 4.8 x 10-13 Which of...
You are instructed to create 400. mL of a 0.39 M phosphate buffer with a pH of 6.2. You have phosphoric acid and the sodium salts NaH2PO4, Na2HPO4, and Na3PO4 available. (Enter all numerical answers to three significant figures.) H3PO4(s) + H20(1) =H30+ (aq) + H2PO4 (aq) Kai = 6.9x10-3 H2PO4 (aq) + H20() = H30+(aq) + HPO42- (aq) Ka2 = 6.2x 10-8 HPO42-(aq) + H20(I) = H30+(aq) + PO43-(aq) Ka3 = 4.8 x 10-13 Which of the available chemicals...