Homework Answers
Answer - C) Add a weak base in water to extract the salt of lll, then add HCl in water to the diethy ether to extract the salt of ll.
ll substrate will react with HCl and dissolve in water layer. Then it can be seperated out since base is already there, so it will precipitate.
When we add weak base, it reacts with lll (Benzoic acid) and it's salt can be taken out.
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Lab 7: Question 5 Homework – Unanswered How would one separate each of I, II and...
Lab 7: Question 7 Homework – Unanswered Why would it be relatively challenging to separate I...
Lab 7: Question 7 Homework – Unanswered Why would it be relatively challenging to separate I and Il via an acid-base extraction? O A Only one of these is soluble in organic solvents O B Both are relatively neutral O C Compound II is more polar
Lab 7: Question 4 Homework. Unanswered What is the purpose of adding aqueous base to extract...
Lab 7: Question 4 Homework. Unanswered What is the purpose of adding aqueous base to extract the acidic components of the unknown mixture? O A Acids and bases afford salts that are water soluble in this experiment O B It moves the compounds of interest to the aqueous layer It enables selective extraction by reacting a weak base and a strong acid followed by reacting a strong base and weak acid, O D all of the above
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in...
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in...
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Acetylation of ferrocene and column chromatography Lab 4: Question 3 Homework • Unanswered Important ... The...
Acetylation of ferrocene and column chromatography
Lab 4: Question 3 Homework • Unanswered Important ... The solvent is changed from petroleum ether to diethyl ether after the ferrocene is collected from the column. Why not use diethyl ether the entire time? Because diethyl ether is more polar than petroleum ether Because petroleum ether selectively elutes ferrocene since it contains more ether oxygens than diethyl ether Because diethyl ether would lead to a poorer separation of ferrocene and acetylferrocene Both a...
Lab 7: Question 6 Homework - Unanswered Why should Il be protonated, rather than deprotonated, in...
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Please help! This is due soon and I don't understand it. A. How would I separate...
Please help! This is due soon and I don't understand it.
A. How would I separate F and G?
B. How would I separate G. and H.?
Separation Options are:
1. suction or gravity filtration
2. aq. NaOH/diethyl ether extraction
3. aq. NaHCO3/diethyl ether extraction
4. silica gel column chromatography
5. evaporation under reduced pressure
6. water/diethyl ether extraction
7. aq. HCL / diethyl ether extraction
OH CI b.p. 302 od b.p. 332 °C
ORGANIC LAB: Separating a Mixture of two Unknowns, different acidity I have a mixture of two unkn...
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3.(16.3) Identify all the correct statements about an acid-base buffer solution. I. It can be prepared...
3.(16.3) Identify all the correct statements about an acid-base buffer solution. I. It can be prepared by combining a strong acid with a salt of its conjugate base. II. It can be prepared by combining a weak acid with a salt of its conjugate base. III. It can be prepared by combining a weak base with its conjugate acid. IV. The pH of a buffer solution does not change when the solution is diluted. V. A buffer solution resists changes...
An unknown mixture (dissolved in diethyl ether) contains only 2 of the following : benzoic acid,...
An unknown mixture (dissolved in diethyl ether) contains only 2 of the following : benzoic acid, phenol, aniline and napthalene. You use the acid-base extraction method and want to identify the 2 compounds in your original mixture. 1) To separate the organic acid you add NaOH and to separate the organic base you add HCl.In both cases these extractions are followed by extractions with water. Why do we add water? Why is this step important? (A clear explanation please). 2)When...
Lab 7: Question 7 Homework – Unanswered Why would it be relatively challenging to separate I and Il via an acid-base extraction? O A Only one of these is soluble in organic solvents O B Both are relatively neutral O C Compound II is more polar
Lab 7: Question 4 Homework. Unanswered What is the purpose of adding aqueous base to extract the acidic components of the unknown mixture? O A Acids and bases afford salts that are water soluble in this experiment O B It moves the compounds of interest to the aqueous layer It enables selective extraction by reacting a weak base and a strong acid followed by reacting a strong base and weak acid, O D all of the above
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Acetylation of ferrocene and column chromatography
Lab 4: Question 3 Homework • Unanswered Important ... The solvent is changed from petroleum ether to diethyl ether after the ferrocene is collected from the column. Why not use diethyl ether the entire time? Because diethyl ether is more polar than petroleum ether Because petroleum ether selectively elutes ferrocene since it contains more ether oxygens than diethyl ether Because diethyl ether would lead to a poorer separation of ferrocene and acetylferrocene Both a...
Lab 7: Question 6 Homework - Unanswered Why should Il be protonated, rather than deprotonated, in order to make it water soluble for extraction from an organic solvent? ♡ on olemas O A The anion derived from Il is too strong and reactive a base to remain stable under aqueous extraction conditions Protonation of amines to form ammonium salts affords a less reactive salt compared to the deprotonation product O C Both a and b are correct
Please help! This is due soon and I don't understand it.
A. How would I separate F and G?
B. How would I separate G. and H.?
Separation Options are:
1. suction or gravity filtration
2. aq. NaOH/diethyl ether extraction
3. aq. NaHCO3/diethyl ether extraction
4. silica gel column chromatography
5. evaporation under reduced pressure
6. water/diethyl ether extraction
7. aq. HCL / diethyl ether extraction
OH CI b.p. 302 od b.p. 332 °C
3.(16.3) Identify all the correct statements about an acid-base buffer solution. I. It can be prepared by combining a strong acid with a salt of its conjugate base. II. It can be prepared by combining a weak acid with a salt of its conjugate base. III. It can be prepared by combining a weak base with its conjugate acid. IV. The pH of a buffer solution does not change when the solution is diluted. V. A buffer solution resists changes...
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