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Lab 7: Question 7 Homework – Unanswered Why would it be relatively challenging to separate I...
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in...
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in...
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Lab 7: Question 6 Homework - Unanswered Why should Il be protonated, rather than deprotonated, in...
Lab 7: Question 6 Homework - Unanswered Why should Il be protonated, rather than deprotonated, in order to make it water soluble for extraction from an organic solvent? ♡ on olemas O A The anion derived from Il is too strong and reactive a base to remain stable under aqueous extraction conditions Protonation of amines to form ammonium salts affords a less reactive salt compared to the deprotonation product O C Both a and b are correct
Lab 7: Question 4 Homework. Unanswered What is the purpose of adding aqueous base to extract...
Lab 7: Question 4 Homework. Unanswered What is the purpose of adding aqueous base to extract the acidic components of the unknown mixture? O A Acids and bases afford salts that are water soluble in this experiment O B It moves the compounds of interest to the aqueous layer It enables selective extraction by reacting a weak base and a strong acid followed by reacting a strong base and weak acid, O D all of the above
Lab 7: Question 2 Homework. Unanswered Why is aqueous NaHCO3 used for the initial extraction of...
Lab 7: Question 2 Homework. Unanswered Why is aqueous NaHCO3 used for the initial extraction of the unknown sample? Why was NaOH not used prior to NaHCO3? O A Because NaHCO3 deprotonates 3-chlorobenzoic acid and NaOH does not O B Because NaOH deprotonates both 3-chlorobenzoic acid and 2-naphthol 0 C Because NaHCO3 deprotonates both 3-chlorobenzoic acid and 2-naphthol
Lab 7: Question 5 Homework – Unanswered How would one separate each of I, II and...
Lab 7: Question 5 Homework – Unanswered How would one separate each of I, II and Ill when dissolved together in diethyl ether? СА Add a weak base in water to extract the salt of III, then add a strong base in water to the diethyl ether to extract the salt of II B O Add a weak h Add a weak base in water to extract the salt of II, then add a strong base in water to the...
Acetylation of ferrocene and column chromatography Lab 4: Question 3 Homework • Unanswered Important ... The...
Acetylation of ferrocene and column chromatography
Lab 4: Question 3 Homework • Unanswered Important ... The solvent is changed from petroleum ether to diethyl ether after the ferrocene is collected from the column. Why not use diethyl ether the entire time? Because diethyl ether is more polar than petroleum ether Because petroleum ether selectively elutes ferrocene since it contains more ether oxygens than diethyl ether Because diethyl ether would lead to a poorer separation of ferrocene and acetylferrocene Both a...
Hello there, I did an extraction of caffeine organic lab experiment. Why is ethyl acetate used...
Hello there, I did an extraction of caffeine organic lab experiment. Why is ethyl acetate used for extracting caffeine and not other solvents? I know that ethyl acetate, caffeine, and water are polar but why are two layers formed after mixing caffeine in water and ethyl acetate? I'm a little confused. I thought that polar mixes with polar and nonpolar mixes with nonpolar. Is caffeine not polar? Is ethyl acetate soluble in water? Please explain. Thank you very much! :)
7. Devise a LLE setup to separate a sample that contains trace levels of three compounds:...
7. Devise a LLE setup to separate a sample that contains trace levels of three compounds: an organic acid, an organic base, and a neutral organic compound. The goal is to have three solutions at the end, each in methylene chloride, one of which contains only the organic acid, the second contains only the organic base, and the third contains only the neutral compound.
Lab 7: Question 1 Homework. Unanswered Which is generally more efficient, extracting an organic layer using...
Lab 7: Question 1 Homework. Unanswered Which is generally more efficient, extracting an organic layer using several smaller portions of water or with one large portion? A several smaller one larger
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Lab 7: Question 6 Homework - Unanswered Why should Il be protonated, rather than deprotonated, in order to make it water soluble for extraction from an organic solvent? ♡ on olemas O A The anion derived from Il is too strong and reactive a base to remain stable under aqueous extraction conditions Protonation of amines to form ammonium salts affords a less reactive salt compared to the deprotonation product O C Both a and b are correct
Lab 7: Question 4 Homework. Unanswered What is the purpose of adding aqueous base to extract the acidic components of the unknown mixture? O A Acids and bases afford salts that are water soluble in this experiment O B It moves the compounds of interest to the aqueous layer It enables selective extraction by reacting a weak base and a strong acid followed by reacting a strong base and weak acid, O D all of the above
Lab 7: Question 2 Homework. Unanswered Why is aqueous NaHCO3 used for the initial extraction of the unknown sample? Why was NaOH not used prior to NaHCO3? O A Because NaHCO3 deprotonates 3-chlorobenzoic acid and NaOH does not O B Because NaOH deprotonates both 3-chlorobenzoic acid and 2-naphthol 0 C Because NaHCO3 deprotonates both 3-chlorobenzoic acid and 2-naphthol
Lab 7: Question 5 Homework – Unanswered How would one separate each of I, II and Ill when dissolved together in diethyl ether? СА Add a weak base in water to extract the salt of III, then add a strong base in water to the diethyl ether to extract the salt of II B O Add a weak h Add a weak base in water to extract the salt of II, then add a strong base in water to the...
Acetylation of ferrocene and column chromatography
Lab 4: Question 3 Homework • Unanswered Important ... The solvent is changed from petroleum ether to diethyl ether after the ferrocene is collected from the column. Why not use diethyl ether the entire time? Because diethyl ether is more polar than petroleum ether Because petroleum ether selectively elutes ferrocene since it contains more ether oxygens than diethyl ether Because diethyl ether would lead to a poorer separation of ferrocene and acetylferrocene Both a...
7. Devise a LLE setup to separate a sample that contains trace levels of three compounds: an organic acid, an organic base, and a neutral organic compound. The goal is to have three solutions at the end, each in methylene chloride, one of which contains only the organic acid, the second contains only the organic base, and the third contains only the neutral compound.
Lab 7: Question 1 Homework. Unanswered Which is generally more efficient, extracting an organic layer using several smaller portions of water or with one large portion? A several smaller one larger
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