Homework Answers
Ans. A
Compounds II and III are water soluble in their neutral form.
Due to ability of formation of hydrogen bonding both alcohol and carboxylic acid form hydrogen bonding with H2O and dissolve in aqueous solutions.so it is difficult to saperate II and III from each other.
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Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in...
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in...
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Lab 7: Question 6 Homework - Unanswered Why should Il be protonated, rather than deprotonated, in...
Lab 7: Question 6 Homework - Unanswered Why should Il be protonated, rather than deprotonated, in order to make it water soluble for extraction from an organic solvent? ♡ on olemas O A The anion derived from Il is too strong and reactive a base to remain stable under aqueous extraction conditions Protonation of amines to form ammonium salts affords a less reactive salt compared to the deprotonation product O C Both a and b are correct
Lab 7: Question 7 Homework – Unanswered Why would it be relatively challenging to separate I...
Lab 7: Question 7 Homework – Unanswered Why would it be relatively challenging to separate I and Il via an acid-base extraction? O A Only one of these is soluble in organic solvents O B Both are relatively neutral O C Compound II is more polar
Lab 7: Question 4 Homework. Unanswered What is the purpose of adding aqueous base to extract...
Lab 7: Question 4 Homework. Unanswered What is the purpose of adding aqueous base to extract the acidic components of the unknown mixture? O A Acids and bases afford salts that are water soluble in this experiment O B It moves the compounds of interest to the aqueous layer It enables selective extraction by reacting a weak base and a strong acid followed by reacting a strong base and weak acid, O D all of the above
Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il
Lab 7: Question 6 Homework - Unanswered Why should Il be protonated, rather than deprotonated, in order to make it water soluble for extraction from an organic solvent? ♡ on olemas O A The anion derived from Il is too strong and reactive a base to remain stable under aqueous extraction conditions Protonation of amines to form ammonium salts affords a less reactive salt compared to the deprotonation product O C Both a and b are correct
Lab 7: Question 7 Homework – Unanswered Why would it be relatively challenging to separate I and Il via an acid-base extraction? O A Only one of these is soluble in organic solvents O B Both are relatively neutral O C Compound II is more polar
Lab 7: Question 4 Homework. Unanswered What is the purpose of adding aqueous base to extract the acidic components of the unknown mixture? O A Acids and bases afford salts that are water soluble in this experiment O B It moves the compounds of interest to the aqueous layer It enables selective extraction by reacting a weak base and a strong acid followed by reacting a strong base and weak acid, O D all of the above
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