Question

Oxidation of Cyclododecanol Reagents used: • Cyclododecanol: 0.50 g • Acetone: 1.2 mL • Acetic acid: 0.4 mL ~ ADDITION OF BLEACH 4.5 ML ~ AN ADDITIONAL 0.4 ML BLEACH ADDED Weight of flask: 36.00g Weight of flask and Cyclododecanol: 36.78g. Weight of Cyclododecanol: 36.00g - 36.78g = 0.78g of Cyclododecanol Is this correct? Please explain. Would the limiting reagent be cyclododecanol? Is this correct? Please explain. What is the percent yield? Please explain. What is the theoretical yield of cyclododecanol? Please explain.

Answer 1

as Yes it is correct. It is oxidation of Cyclododecanol where change in oxidation state can be found by desermining oxidation state of a Carbon atom. b Yes Cyclododecanol is limiting reagent. It is the limiting member of reaction. Therefore, the number of moles of theoretical product should be equal to the number of moles of Cyclodo decanol used. cr Percent yield. It is the percent ratio of actual gield to the theoretical yield. It is calculated as s. yield - Actual yield x 1000% Theoretical yield is. yield = 0.789 x 100 = 143.38% 0.53989 de Theoretical yield: - It is the number of moles of the product by the molecular weight of product det mmol of Cyclodo decanol is 2.9839 mmols And molecular weight of Cyclo do decanol - 18H.329. : Theoretical yiek of Cyclododecanol - 2.9939 184.329. = 0.543989 Based on molecular weight of product, the theoretical yield should have a mass of 0.543989.