Molarity of solution 1 (M1) = 1.4 M ...(given)
Volume of solution 1 (V1) = 200 ml ...(given)
Molarity of solution 2 (M2) = 1 M ....(given)
Volume of solution 2 (V2) = ?
We know, concentration equation is -
M1 V1 = M2V2
So,
1.4 M × 200 ml = 1 M × V2
1.4 M × 200 ml / 1 M = V2
280 ml = V2
This V2 is the final volume of 1M solution.
Initial volume of solution was = 200mL
Amount of water added = 280 - 200 = 80mL
Thus we need to add 80mL of distilled water to 1.4M , 200ml solution to make it 1M .
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