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A 2.5 g piece of lithium metal is dropped into a 500.0 g sample of water at 22.1°C. The temperature of the water increases to
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Answer #1

Hi there,

1)

Lithium reacts violently with water and produces heat energy, hydrogen gas, and lithium hydroxide

2 Li(s) + 2 H2O(l) => 2 LiOH(aq) + H2(g)

Answer: Lithium reaction with water is exothermic (heat released), because metallic bond breaks in lithium metal and solvolysis (hydrolysis) releases energy.

2)

we have to use the equation

Q = m x Cs x ΔT

mcΔT = Q: m = mass; c = specific heat: ΔT = temp. difference; Q = Heat absorbed or Released.

Q = 500 g x 4.184 J/g.0C x (23.5 - 22.1) 0C = 2928.8 J

Energy released = 2929 J = 2.93 kJ

3)

from above energy released = 2.93 kJ ( 1 kJ = 1000 J)

heat released by lithium in reaction = 2.93 kJ / 2.5 g = 1.17 kJ/g

heat released by lithium in reaction = 1.17 kJ/g

Hope this helped you!

Thank You So Much!

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