Question

The first step in the metabolic breakdown of glucose is its phosphorylation to G6P:

glucose(aq)+ATP(aq)→G6P(aq)+ADP(aq)+H+(aq)glucose(aq)+ATP(aq)→G6P(aq)+ADP(aq)+H+(aq)

The standard reaction Gibbs energy for the reaction isΔGoΔGo= -34 kJ/mol at 37°C

A.

Calculate the biological standard reaction GIbbs energy for the reaction at 37°C.

B. Calculate the equilibrium constant of the reaction in the thermodynamic standard (KeqKeq) at 37°C. Use 2 significant figures.

c, Calculate the equilibrium constant of the reaction in the biological standard (K′eqKeq′) at 37°C. Use 2 significant figures.

Answer 1

for a reaction : A+B rightowe AB + 2 H+ (aq) OGO! 0Gº+(-9)RT * 1x in (10) "A glucose (ag It ATP (ang) → G6P (0g ) +Applag )+H°09.) od standard condition (ht] {m, but at biological condition (standard) pH az ie (H+] = 107 T: 37 c = 273.15 +37= 310.15k 40°, 4G (-)RT 1 1 1 1010 port to =-34 X103 61 mod –14831455/k.mel x 310-15kxFalnio = -34 X10 3 slmol - 41564-415/mol -75564-4 Timol = -7556 kilmol. -75 kílmol. (2 sigraficant figure) OGº! - RT in ka' -> Int's -669-6-75584• 4 71.mel) RT 8:31465/mel x 31015% inkels 09303 => keq p09:303 53.280012 kg - kie' (anat) port 4