11. Glucose and fructose exist in equilibrium. If 0.244 M fructose at 25°C is prepared, what...
Consider the given interconversion, which occurs in glycolysis. fructose 6-phosphate glucose 6-phosphate K1.97 What is AG for the reaction (K measured at 25 °C)? AG -1680.9 kJ/mol If the concentration of fructose 6-phosphate is adjusted to 1.4 M and that of glucose 6-phosphate is adjusted to 0.75 M, what is AG? AG =-4402.59 kJ/mol Which statements are consistent with the conditions at which AG is measured? The temperature is 273 K. The initial concentrations of reactant and product are 1...
Calculate the equilibrium concentrations of N2O4 and NO2 at 25 ∘C if the initial concentrations are [N2O4]= 0.0130 M and [NO2]= 0.0300 M. The equilibrium constant Kc for the reaction N2O4(g)⇌2NO2(g) is 4.64×10−3 at 25 ∘C. I've worked through this problem a few times and still don't get the right answer. Can anyone show me the work??
Calculate the equilibrium concentrations of N2O4and NO2 at 25 ∘C if the initial concentrations are [N2O4]= 0.0150 M and [NO2]= 0.0360 M. The equilibrium constant Kc for the reaction N2O4(g)⇌2NO2(g) is 4.64×10−3 at 25 ∘C. Part A Calculate the equilibrium concentration of N2O4. Express your answer with the appropriate units. Part B Calculate the equilibrium concentration of NO2. Express your answer with the appropriate units.
a. through c. please!
Question #2 Consider the following reaction: 1. If a solution of fructose-1-phosphate is incubated with a catalytic amount of enzyme X, the fructose-1-phosphate is transformed to fructose-6-phosphate. At equilibrium, the concentrations of the reaction components are fructose-1-phosphate <-> fructose-6-phosphate 10 mM 40 mM a. Calculate K'eq for this reaction at 25°C. b. Calculate AG" for this reaction at 25°C. (use Gas constant-R=8J/molK) c. If the concentration of fructose-1-phosphate is adjusted to 20 M and the concentration...
Glucose-6-P isomerase catalyses the following glycolytic reaction: Glucose-6-P (G6P) fructose-6-P G=1700 kJ/mol (Change in free energy) If 7.2 g of G6P* is dissolved in 980 mL of buffer and 150 µL of this is incubated with enzyme at 25°C & 37°C, what would be the equilibrium concentration of F6P at these two temperatures? [15 marks] *- The periodic table may be used to determine the molecular weight of G6P
The equilibrium constant K for the reaction fructose-1,6-diphosphate, is 8.9 x 10-5 Mat 25°C and we can assume the behavior to be ideal. glyceraldehyde-3-phosphate + dihydroxyacetone phosphate a. Calculate AGº for the process (standard state: 1M) b. Suppose that we have a mixture that is initially 0.01M in fructose-1,6-diphosphate and 105 M in both glyceraldehyde-3-phosphate and dihydroxyacetone phosphate. What is AG? in which direction will the reaction occur?
What are the equilibrium concentrations? Equation
sheetincluded.
2. (10 pts) For the reaction (aq) the equilibrium constant is Kc 3.0 x 10's at 25 oC. If the initial concentration of IHA is 0.100 M, what are the equilibrium concentrations of HA, H3o and A"?
Question #2 Consider the following reaction: 1. If a solution of fructose-1-phosphate is incubated with a catalytic amount of enzyme X, the fructose-1-phosphate is transformed to fructose-6-phosphate. At equilibrium, the concentrations of the reaction components are fructose-1-phosphate <> fructose-6-phosphate 10 mM 40 mM a. Calculate K'eq for this reaction at 25°C. b. Calculate AG" for this reaction at 25°C. (use Gas constant-R=8 J/molK) c. If the concentration of fructose-1-phosphate is adjusted to 20 M and the concentration of fructose-6-phosphate is...
Calculate the equilibrium concentrations of N2O4 and NO2 at 25 ∘C in a vessel that contains an initial N2O4 concentration of 0.0551 M . The equilibrium constant Kc for the reaction N2O4(g)⇌2NO2(g) is 4.64×10−3 at 25 ∘C. Express your answers using four decimal places separated by a comma. Hi. I don't know how to solve this problem. I would appreciate if you could go in details. Thank you so much.
Calculate the equilibrium concentrations of N2O4 and NO2 at 25°C in a vessel that contains initial concentration of 0.0500M of N2O4. KC = 4.64 × 10-3 at 25°C. N2O4 (g) 2NO2 (g)