A gas mixture contains 0.165 mol C2H6(g) and 0.233 mol O2(g). What is the mole fraction...

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A gas mixture contains 0.165 mol C2H6(g) and 0.233 mol O2(g). What is the mole fraction of O2(g) in the mixture

Answer 1

Answer #1

$Answer: Mole of Cho (9) = 0.165 mol Mole of ozo = 0.233 rust Mole fraction (A)= mole of A more of a tree of B More trachan of$

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Answer 2

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