Convert 3.27 g of Ni2O3 to grams of Ni
Convert 5.75x1024 molecules of Ni2O3 to grams of O2
2 Ni2O3 (s)
4 Ni(s) + 3 O2 (g)
(1) Given : 3.27 g of Ni2O3
Molar mass of Ni2O3 = 165.3 g/mol
Moles of Ni2O3 = given mass / molar mass
= 3.27 / 165.3
= 0.0197 mole
According to above balanced reaction
2 moles of Ni2O3 react to form 4 moles of Ni
0.0197 moles of Ni2O3 react to form =(4 x 0.0197)/2
= 0.0394 mole of Ni
To convert in grams
Mass of Ni = moles x molar mass
Molar mass of Ni = 58.6 g/mol
So, mass of Ni = 0.0394 x 58.6
= 2.30 g of Ni
(2) Given : 5.75 x 1024 molecules of Ni2O3
6.023 x 1023 molecules = 1 mole
5.75 x 1024 molecules = (1 x 5.75 x 1024)/6.023 x 1023
= 9.54 moles of Ni2O3
According to above reaction
2 moles of Ni2O3 react to form 3 moles of O2
9.54 moles of Ni2O3 react to form = (3 x 9.54 )/2
= 14.31 moles of O2
Molas mass of O2 = 32 g/mol
So, mass of O2 = moles x molar mass
= 457.9 g of O2
Convert 3.27 g of Ni2O3 to grams of Ni Convert 5.75x1024 molecules of Ni2O3 to grams...
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