Table 1. The results of adding solid Mg(OH)2 to 10.0L of water. Total amount of Mg(OH)2...

Question

Question

Answer 1

Answer #1

Mass of grams of Mg(OH)2 dissolve = Total amount of Mg(OH)2 added - Mass of Mg(OH)2 that does not dissolve

so for entry Number 5: 0.09700 - 0.0007 = 0.0963 gram

entry number 6: 0.1 - 0.0037 = 0.0963 gram

entry number 7: 0.015 - 0.0537 = 0.0963 gram

entry number 8: 0.2 - 0.1037 = 0.0963 gram

so in all cases total amount of Mg(OH)2 dissolve is 0.0963 gram

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No of mole = given mass/ molar mass

so given mass is 0.0963 gram and molar mass of Mg(OH)2 = 58.326 so

No of moles dissolves 0.0963/58.326 = 1.65 x 10-3

Answer 2

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