What volume of a 3.00 M KI stock solution would you use to make 0.300 L...

Question

Question

Answer 1

Answer #1

Answer:- 0.125 L or 125 mL

Solution:-

since we know that by dilution law

N1V1 = N2V 2

it is given that

N2 = 3.00 M

V2 = ???

V1 =0.300 L

N1 = 1.25M

V2 = N1V1 / N2

V2 = 1.25 * 0.300 / 3.00

V2 = 0.125 L or 125 mL

please rate my answer

Add a comment

Answer 2

Similar Homework Help Questions

You wish to make a 0.135 M nitric acid solution from a stock solution of 3.00...

You wish to make a 0.135 M nitric acid solution from a stock solution of 3.00 M nitric acid. How much concentrated acid must you add to obtain a total volume of 150 mL of the dilute solution? ml
(a) How many milliliters of a stock solution of 11.0 M HNO, would you have to...

(a) How many milliliters of a stock solution of 11.0 M HNO, would you have to use to prepare 500 mL of 0.200 M HNO,? ml (b) If you dilute 21.0 mL of the stock solution from part a) to a final volume of 3.00 L, what will be the concentration of the diluted solution? (Watch the 7. -13 points My (a) How many milliliters of a stock solution of 12.0 M HNO, would you have to use to prepare...
What volume of a 6.50 M NaNO3 solution should you use to make 0.575 L of...

What volume of a 6.50 M NaNO3 solution should you use to make 0.575 L of a 1.60 M NaNO3 solution? 1000 mL = 1L 405 mL red 93.0 mL 215 mL uswer 142 mL

You wish to make a 0.257 M nitric acid solution from a stock solution of 3.00...

You wish to make a 0.257 M nitric acid solution from a stock solution of 3.00 M nitric acid. How much concentrated acid must you add to obtain a total volume of 50.0 mL of the dilute solution? Submit Answer Retry Entire Group 9 more group attempts remaining
8. What volume of a 5.00 M NaNO3 solution should you use to make 0.500 L...

8. What volume of a 5.00 M NaNO3 solution should you use to make 0.500 L of a 1.50 M NaNO3 solution? 9. What volume (in mL) of a 0.230 M HNO3 solution will completely react with 21.3 mL of a 0.125 M Na2CO3 solution according to this balanced chemical equation? NazCO3(aq) + 2 HNO3(aq) → 2 NaNO3(aq) + CO2(g) + H200)_
What volume (in L) of 0.300 M LiI will react with 0.150 L of a 0.175...

What volume (in L) of 0.300 M LiI will react with 0.150 L of a 0.175 M Pb(NO3)2 solution according to the following balanced chemical equation? 2LiI(aq) + Pb(NO3)2(aq) ⟶⟶ ⟶⟶ PbI2(s) + 2LiNO3(aq)

if 6.25 g of CuNO3 is dissolved in water to make a 0.300 M solution, what...

if 6.25 g of CuNO3 is dissolved in water to make a 0.300 M solution, what is the volume of the solution in milliliters
What volume of 4.05 M NaCl is needed to make 500 mL of 0.300 M NaCl...

What volume of 4.05 M NaCl is needed to make 500 mL of 0.300 M NaCl solution? _____ mL (Report your answer with correct sig figs in units of mL)
What volume of a 5.50 M solution of NaNO3 do you need to make 0.550 L...

What volume of a 5.50 M solution of NaNO3 do you need to make 0.550 L of a 1.70 M solution of NaNO3? Express the volume to three significant figures and include the appropriate units.

1b. You wish to make a 0.395 M perchloric acid solution from a stock solution of...

1b. You wish to make a 0.395 M perchloric acid solution from a stock solution of 3.00 M perchloric acid. How much concentrated acid must you add to obtain a total volume of 75.0 mL of the dilute solution? 1c. In the laboratory you dilute 4.36 mL of a concentrated 12.0 M perchloric acid solution to a total volume of 50.0 mL. What is the concentration of the dilute solution?