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![Givens 2 Norg) + (g) - 2Nocelo) Nolinitial [ce, Pritial Baitial rate ( 0.44M 0.21M 23 - ar min) OYUN 0,88 % 042M r = k [no]](http://img.homeworklib.com/questions/966c7f20-dacf-11eb-be29-a9508a963efc.png?x-oss-process=image/resize,w_560)
![page 2 = 2.046 &- 2.05 I part-1- Part 2: Part 3 nate kno] ² [Cl] Order of reaction with respect to No = 12 Order of reaction](http://img.homeworklib.com/questions/976dfb00-dacf-11eb-bc76-e98293019198.png?x-oss-process=image/resize,w_560)
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The reaction 2NO(g) + Cl2(9) - 2NOCI(9) was studied at a constant temperature and the following...
it's asking for the rate constant pr The reaction pt 2NO(9) + Cl2(g) + 2NOCI(9) pr...
it's asking for the rate constant
pr The reaction pt 2NO(9) + Cl2(g) + 2NOCI(9) pr was studied at -10°C. The following results were obtained where pt pt Rate = A[Cl] At pt pt [NO], (mol/L) 0.060 0.060 0.12 (Cl2], (mol/L) 0.060 0.12 0.12 Initial Rate (mol/L min) 0.039 0.078 0.311 1 pt 1 pt
Select all that apply. The rate law for the reaction 2NO(g) + Cl2(g) → 2NOCI(g) is...
Select all that apply. The rate law for the reaction 2NO(g) + Cl2(g) → 2NOCI(g) is given by R-k[NO][C121 If the following is the mechanism for the reaction, NO(g) + Cl2(g) → NOC12(g) NOCI,(g) + NO(g) → 2NOCI(g) which of the following statements accurately describes this reaction? Check all that apply. 2nd order reaction The first step is the slow step. Doubling [NO] would quadruple the rate. Cutting (Cl) in half would decrease the rate by a factor of two....
Part A Consider the reaction between NO and Cl2 to form NOCI: 2NO (9) + Cl2...
Part A Consider the reaction between NO and Cl2 to form NOCI: 2NO (9) + Cl2 (9)=2NOCI (9) A reaction mixture at a certain temperature initially contains only (NO) = 0.60 M and (Cl) = 0.63 M. After the reaction comes to equilibrium, the concentration of NOCI is 0.22 M. You may want to reference (Page 688) Section 15.6 while completing this problem. Find the value of the equilibrium constant (K) at this temperature. Express your answer using two significant...
Chapter 13, Question 9 For the reaction 2NO + Cl2 + 2NOCI, do the following: Express...
Chapter 13, Question 9 For the reaction 2NO + Cl2 + 2NOCI, do the following: Express the rate in terms of the disappearance of Cl2. Rate = _ A[cz] Rate=(-)(A[cz] 4) LINK TO TEXT We were unable to transcribe this imageIf Cl2 reacts at a rate of 79 M/s, state how fast NOCI will form. M/s exact number, no tolerance
5. The reaction 2NO+ Cl2 → 2NOCI is thought to occur in two steps, as shown...
5. The reaction 2NO+ Cl2 → 2NOCI is thought to occur in two steps, as shown by the following proposed mechanism: O NO + Cl2 NOCI (fast, at equilibrium) (i) NO + NOCI, → 2NOCI (slow) What rate law does this mechanism predict? Select the best choice by circling it. a. rate = ** [NO]?[NOCI] rate = *, [NO]2 C. rate = [NOCL] d. rate = kek [NO](C1,12 rate = [NO] f. rate = kaka [NO]+[C12] g. rate = kak2...
10. Examine the reaction: 2NOCI(g) 2NO (g) + Cl2(g) When the above reaction reaches equilibrium the...
10. Examine the reaction: 2NOCI(g) 2NO (g) + Cl2(g) When the above reaction reaches equilibrium the concentration of each component is [NOCI] = 2.9 M. [NO] =1.1 Mand [Cl2] = 0.65 M. What is the equilibrium constant, K for this reaction? Does the equilibrium lie on the left side or the right side of the equilibrium? 9. The following equilibrium is endothermic. In the box below, show how the reaction will shift response to the indicated stress by writing,, or...
63. At 35°C, K = 1.6 x 10-6 for the reaction 2NOCI(9) = 2NO(g) + Cl2...
63. At 35°C, K = 1.6 x 10-6 for the reaction 2NOCI(9) = 2NO(g) + Cl2 (9) Calculate the concentrations of all species at equilibrium for each of the following original mixtures. a. 2.0 moles of pure NOCI in a 2.0-L flask Answer b. 1.0 mole of NOCI and 1.0 mole of NO in a 1.0-L flask Answer c. 2.0 moles of NOCI and 1.0 mole of Cl, in a 1.0-L flask
Item 6 Part A Consider the reaction between NO and Cl, to form NOCI: 2NO (9)...
Item 6 Part A Consider the reaction between NO and Cl, to form NOCI: 2NO (9) + Cl2 (9) = 2NOCI (9) A reaction mixture at a certain temperature initially contains only (NO) = 0.53 M and (Cl2] = 0.53 M. After the reaction comes to equilibrium, the concentration of NOCI is 0.40 M. You may want to reference (Page 688) Section 15.6 while completing this problem. Find the value of the equilibrium constant (K) at this temperature. Express your...
2NO (g) +Cl2 (g) → NOCl (g) Experiment concentration of NO (M) concentration of Cl2(M) Rate...
2NO (g) +Cl2 (g) → NOCl (g) Experiment concentration of NO (M) concentration of Cl2(M) Rate (M/s) 1 0.05 0.01 3.40 x 10-4 2 0.025 0.01 8.50 x 10-5 3 0.025 0.04 3.40 x 10-4 What is the reaction order with respect to NO ? the reaction order with respect to reaction order to Cl2 ? overall reaction order ? what is the rate constant ?
2NO (g) +Cl2 (g) → NOCI (g) Experiment concentration of NO (M) 0.096 concentration of Cl2(M)...
2NO (g) +Cl2 (g) → NOCI (g) Experiment concentration of NO (M) 0.096 concentration of Cl2(M) Rate (M/s) 0.05 3.40 x 10-4 0.05 8.50 x 10-5 0.10 3.40 x 10-4 0.024 0.024 What is the reaction order with respect to NO ? the reaction order with respect to reaction order to Cl2 ? overall reaction order ? what is the rate constant * All orders are integers * Rate constant: Please report 3 significant figures. Numbers only, No unit. No...
it's asking for the rate constant
pr The reaction pt 2NO(9) + Cl2(g) + 2NOCI(9) pr was studied at -10°C. The following results were obtained where pt pt Rate = A[Cl] At pt pt [NO], (mol/L) 0.060 0.060 0.12 (Cl2], (mol/L) 0.060 0.12 0.12 Initial Rate (mol/L min) 0.039 0.078 0.311 1 pt 1 pt
Select all that apply. The rate law for the reaction 2NO(g) + Cl2(g) → 2NOCI(g) is given by R-k[NO][C121 If the following is the mechanism for the reaction, NO(g) + Cl2(g) → NOC12(g) NOCI,(g) + NO(g) → 2NOCI(g) which of the following statements accurately describes this reaction? Check all that apply. 2nd order reaction The first step is the slow step. Doubling [NO] would quadruple the rate. Cutting (Cl) in half would decrease the rate by a factor of two....
Part A Consider the reaction between NO and Cl2 to form NOCI: 2NO (9) + Cl2 (9)=2NOCI (9) A reaction mixture at a certain temperature initially contains only (NO) = 0.60 M and (Cl) = 0.63 M. After the reaction comes to equilibrium, the concentration of NOCI is 0.22 M. You may want to reference (Page 688) Section 15.6 while completing this problem. Find the value of the equilibrium constant (K) at this temperature. Express your answer using two significant...
Chapter 13, Question 9 For the reaction 2NO + Cl2 + 2NOCI, do the following: Express the rate in terms of the disappearance of Cl2. Rate = _ A[cz] Rate=(-)(A[cz] 4) LINK TO TEXT We were unable to transcribe this imageIf Cl2 reacts at a rate of 79 M/s, state how fast NOCI will form. M/s exact number, no tolerance
5. The reaction 2NO+ Cl2 → 2NOCI is thought to occur in two steps, as shown by the following proposed mechanism: O NO + Cl2 NOCI (fast, at equilibrium) (i) NO + NOCI, → 2NOCI (slow) What rate law does this mechanism predict? Select the best choice by circling it. a. rate = ** [NO]?[NOCI] rate = *, [NO]2 C. rate = [NOCL] d. rate = kek [NO](C1,12 rate = [NO] f. rate = kaka [NO]+[C12] g. rate = kak2...
10. Examine the reaction: 2NOCI(g) 2NO (g) + Cl2(g) When the above reaction reaches equilibrium the concentration of each component is [NOCI] = 2.9 M. [NO] =1.1 Mand [Cl2] = 0.65 M. What is the equilibrium constant, K for this reaction? Does the equilibrium lie on the left side or the right side of the equilibrium? 9. The following equilibrium is endothermic. In the box below, show how the reaction will shift response to the indicated stress by writing,, or...
63. At 35°C, K = 1.6 x 10-6 for the reaction 2NOCI(9) = 2NO(g) + Cl2 (9) Calculate the concentrations of all species at equilibrium for each of the following original mixtures. a. 2.0 moles of pure NOCI in a 2.0-L flask Answer b. 1.0 mole of NOCI and 1.0 mole of NO in a 1.0-L flask Answer c. 2.0 moles of NOCI and 1.0 mole of Cl, in a 1.0-L flask
Item 6 Part A Consider the reaction between NO and Cl, to form NOCI: 2NO (9) + Cl2 (9) = 2NOCI (9) A reaction mixture at a certain temperature initially contains only (NO) = 0.53 M and (Cl2] = 0.53 M. After the reaction comes to equilibrium, the concentration of NOCI is 0.40 M. You may want to reference (Page 688) Section 15.6 while completing this problem. Find the value of the equilibrium constant (K) at this temperature. Express your...
2NO (g) +Cl2 (g) → NOCI (g) Experiment concentration of NO (M) 0.096 concentration of Cl2(M) Rate (M/s) 0.05 3.40 x 10-4 0.05 8.50 x 10-5 0.10 3.40 x 10-4 0.024 0.024 What is the reaction order with respect to NO ? the reaction order with respect to reaction order to Cl2 ? overall reaction order ? what is the rate constant * All orders are integers * Rate constant: Please report 3 significant figures. Numbers only, No unit. No...
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