Question

Consider the unbalanced reaction between silver nitrate and sodium chromate:

AgNO3(aq) + Na2CrO4(aq) → Ag2CrO4(s) + NaNO3(aq)

What mass of silver chromate (in grams) will be produced when 100.0 mL of 2.30 M silver nitrate is mixed with 300.0 mL of 1.40 M sodium chromate?

Using the information from above, determine the concentration of the sodium ions left in solution after the reaction is complete.

Using the information from above, determine the concentration of the nitrate ions left in solution after the reaction is complete.

Using the information from above, determine the concentration of the silver ions left in solution after the reaction is complete.

Using the information from above, determine the concentration of the chromate ions left in solution after the reaction is complete.

Answer 1

Ndume MO 4. Ра No2 + а, сло4 – "Аа, Croa - ул. No 3 Guien, . volume of Ag No3 = 100 ml 0.1 L . Molarity of Ag Nog = 2.3 M. Moles 3 Ay No3 : molavily x volumu - 2:3x0.1 - 60073 moles volume & Na, Qoy : soome moles: Molaulj x van locality of Naztrog 1.10m ; 7300L X1.4 = 0.42 moles, from Run, 2 mole of AgNO3 react with : 1 mole of Nazorog 0 3 moles : 0.23 x 4 .115 moles of Naz Cou z Ag Noz react with 1. AgNO3 is present in loves quantity no. Ag Nez will be left ... the [^g*], [ woj] will be zero moms į Naziren lift -0142 - O'ls moke - WLOBO 0.305 Volume - 0100L 40:31 04 corice = 0.305 -10.7625! 04 Naz Croa 2 Nat et croq² - 0.7625 M 2X 0.7615 To 7625 ML. 1.525M] = from Rxn we see a more of AgNO3 prodo 0. 23 mole of A Noz produas = 331 13 x 2 - gm. In Na, Croa more of AJ Nos producers Imole of Alz Croq 2 331.139 produas =*331.73% 0.23.=138 · 1489590 of J Nog