Question

Pre-Lab Questions 1. Write the formula and determine the molar mass for the metal carbonate of each of the first three elements in Group 1. 2. If 2.175 g of each metal carbonate were weighted out, how many moles of each substance would you have Calculate the number of moles of CaCl2 in 125 mL of 0.2 M CaCl solution.

Answer 1

ree elements en group 1 are li, Na and k (Lithum, sodium and potessium) and the formulas of these - carbonetes are. La coz ( Lithum carbonate) Molar Mess of li₂CO3 = 2x7 + 12 + 16 = 74 g/mol Na coz (sodium carbonate) Molar Mess of NaCO3 = 2*23 + 12 + 3x16 = 106 g/mol &CO3 ( Potassium Carbonete) Molar Mess of & Co z = 2x39 + 12 + 3x16 = 138g/mol » Moles of 4, com having 2.115g weight 21759 43 63 x Imole 4,63 = 0.0293 miles of Liz coz . 74g 603 - Moles of Na coz having 2.115g weight 2.115g Macos x Imate blanco y = 0.0201 miles of N9,693 . 10bga Nyco мал + к, х Вэма 2.1702 vеr-F 2:1754 $coz x Imole of Boy. 0.0158 moles of K, C3 130g Blog 0.020 0.0158

Molarity is defined as the number of moles of solute per life of solution no. of moles of solute (cack) Molarity of solution - volume of solution in likes lum Curen. volume Molarity of solution = 0.2M ! volume of solution - 125 mL = 0.125 Lite substitute this value in above expression. am no-of moler of solute (ack) 0.2M= 0.125 Like no.rf moles of cacę = 0.280 125 mole I no. of moles of calų = 0.025 mole